The partial derivative in relation to x: dz/dx=-y
The partial derivative in relation to y: dz/dy= x
If its a equation where a constant 'c' is set equal to the equation c = x - y, the derivative is 0 = 1 - dy/dx, so dy/dx = 1
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xy - xy = 0
Well if you have found the derivative (slope of the tangent line) of the curve at that point and you know the xy coordinates for that point in the curve then you set it up in y=mx+b format where y is your y-coordinate, x is your x-coordinate and m is your derivative and solve for b
The GCF is xy
Half of XY...
If you mean: xy2/xy then it can be simplified to y