xy - xy = 0
Well if you have found the derivative (slope of the tangent line) of the curve at that point and you know the xy coordinates for that point in the curve then you set it up in y=mx+b format where y is your y-coordinate, x is your x-coordinate and m is your derivative and solve for b
The GCF is xy
Half of XY...
If you mean: xy2/xy then it can be simplified to y
f'(x)xy=yx(y-1) f'(x)2=2x1=2x
With respect to x, the derivative would be:1*Y^3 = Y^3With respect to Y the derivative would be:3*xy^2 - 3In general: the derivative of a variable is defined as: nax^n-1Where n represents the power, a represents the factor and x represents the variable
Algebraic expressions have derivatives. Equations have solutions (sometimes). I suppose you could dfferentiate each term of this equation with respect to x: cos(xy) gives -sin(xy)(y+xdy/dx), -y3 gives -3y2dy/dx, and 4x2y gives 8xy +4x2dy/dx
xy - xy = 0
xy + xy = 2xy
Well if you have found the derivative (slope of the tangent line) of the curve at that point and you know the xy coordinates for that point in the curve then you set it up in y=mx+b format where y is your y-coordinate, x is your x-coordinate and m is your derivative and solve for b
XY
It is an expression in the form of: xy+7
"Derivative of"
The answer depends on whether xy are commutative numbers or operators in a permutation group.
The GCF is xy
Half of XY...