116
53.85164807' by means of Pythagoras.
I would say that the easiest way is with proportions. Say you need to figure what percent of 10 is 5. 5 x _ = _ 10 100 10x=500 ______ 10 10 x= 50 what is 50% of 10 x 50 __ = __ 10 100 100x=500 ________ 100 100 x=5 5 is 50% of what 5 50 _ = __ x 100 50x=500 ________ 50 50 x=10
60 percent of 50 = 60% x 50 = (60/100) x 50 = 0,6 * 50 = 30
%rate: = (16/50) x 100% = 0.32 x 100% = 32%
42
x + 50 = 2x + 100 50 = 2x+100-x 50 = x + 100 50-100=x -50=x -50+50=0 -100+100=0 it is zero
If diagonal is 10 then each side is sqrt 50 (Pythagoras) and area is sqrt 50 x sqrt 50 ie 50
116
If it is a 2-D box then 70.71
50% of 100 = 50% x 100 = 0.50 x 100 = 50
53.85164807' by means of Pythagoras.
50 since there are 100 vertices ("gons") and it takes two vertices to connect a diagonal, there will be 50 diagonals.
% rate:= (50/220) x 100%= 0.2273 x 100%= 22.73%
10 x 10=100 20 x 5=100 50 x 2= 50 100 x 1=
x/y*100=% For example: 45/90*100=% 1/2*100=% .5*100=% 50=% Check: 50% of 90 = x 50/100 * 90 = x .5 * 90 = x 45 = x
% change =[(50-40)/50] x 100% = 20% (decrease)