If it is a 2-D box then 70.71
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If the diagonal is 10 we know all sides are equal so from pythagoraen theorem each side is 7.07 inch length Area = 7.07 x 7.07 = 50
60.28 is the length of the diagonal, got through Pythagoras' Theorem.
Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length). so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units. As a square has sides of equal length the square on one side is actually the area of the square. i.e. the area of a square with a diagonal of 10 units is 50 square units. or generically the area of a square with a diagonal of length 'x' = (x2)/2
To find the volume of a rectangular box, you multiply its length, width, and height together. In this case, the length is 50 cm, the width is 40 cm, and the height is 30 cm. Therefore, the volume of the rectangular box would be 50 cm x 40 cm x 30 cm = 60,000 cubic centimeters.
To find the side length of a square with a diagonal of 5, we can use the Pythagorean theorem. The diagonal of a square divides it into two 45-45-90 right triangles. Let x be the side length of the square. Using the Pythagorean theorem, we have x^2 + x^2 = 5^2. Simplifying, we get 2x^2 = 25. Solving for x, we find x = √(25/2) = √12.5 = 3.54 (rounded to two decimal places). Therefore, the side length of the square is approximately 3.54 units.