If the diagonal is 10 we know all sides are equal so from pythagoraen theorem each side is 7.07 inch length Area = 7.07 x 7.07 = 50
60.28 is the length of the diagonal, got through Pythagoras' Theorem.
Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length). so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units. As a square has sides of equal length the square on one side is actually the area of the square. i.e. the area of a square with a diagonal of 10 units is 50 square units. or generically the area of a square with a diagonal of length 'x' = (x2)/2
Since a square has right angles, you can use the Pythagorean Theorem to calculate the diagonal. Specifically, the diagonal of a square is equal to the length of a side, multiplied by the square root of 2.
Volume = Height x width x length
36
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
42
If the diagonal is 10 we know all sides are equal so from pythagoraen theorem each side is 7.07 inch length Area = 7.07 x 7.07 = 50
Assuming the lengths refer to the sides of a rectangle (rather than some other shape), the length of the diagonal is sqrt(50^2 + 100^2) = 50*sqrt(1^2 + 2^2) = 50*sqrt(5) = 111.80, rounded to 2 decimal places.
If diagonal is 10 then each side is sqrt 50 (Pythagoras) and area is sqrt 50 x sqrt 50 ie 50
60.28 is the length of the diagonal, got through Pythagoras' Theorem.
appx. 30' 4.9"
If you know its dimensions then use Pythagoras' theorem to find the length of its diagonals.
The diagonal of a square = the length of one side x the square root of 2 (approx 1.414)
d=x√2 where d is a diagonal and x is a side d=80√2 (or 113.137)
53.85164807' by means of Pythagoras.