If the diagonal is 10 we know all sides are equal so from pythagoraen theorem each side is 7.07 inch length Area = 7.07 x 7.07 = 50
60.28 is the length of the diagonal, got through Pythagoras' Theorem.
Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length). so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units. As a square has sides of equal length the square on one side is actually the area of the square. i.e. the area of a square with a diagonal of 10 units is 50 square units. or generically the area of a square with a diagonal of length 'x' = (x2)/2
To find the volume of a rectangular box, you multiply its length, width, and height together. In this case, the length is 50 cm, the width is 40 cm, and the height is 30 cm. Therefore, the volume of the rectangular box would be 50 cm x 40 cm x 30 cm = 60,000 cubic centimeters.
To find the side length of a square with a diagonal of 5, we can use the Pythagorean theorem. The diagonal of a square divides it into two 45-45-90 right triangles. Let x be the side length of the square. Using the Pythagorean theorem, we have x^2 + x^2 = 5^2. Simplifying, we get 2x^2 = 25. Solving for x, we find x = √(25/2) = √12.5 = 3.54 (rounded to two decimal places). Therefore, the side length of the square is approximately 3.54 units.
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To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem, which states that the square of the length of the diagonal is equal to the sum of the squares of the lengths of the two sides. In this case, the diagonal length (d) can be calculated as follows: d^2 = 30^2 + 50^2. Therefore, d^2 = 900 + 2500 = 3400. Taking the square root of 3400 gives us the diagonal length, which is approximately 58.3 feet.
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 40' x 50' rectangle can be calculated as follows: diagonal = √(40^2 + 50^2) = √(1600 + 2500) = √4100 ≈ 64.03 feet.
If the diagonal is 10 we know all sides are equal so from pythagoraen theorem each side is 7.07 inch length Area = 7.07 x 7.07 = 50
Assuming the lengths refer to the sides of a rectangle (rather than some other shape), the length of the diagonal is sqrt(50^2 + 100^2) = 50*sqrt(1^2 + 2^2) = 50*sqrt(5) = 111.80, rounded to 2 decimal places.
If diagonal is 10 then each side is sqrt 50 (Pythagoras) and area is sqrt 50 x sqrt 50 ie 50
60.28 is the length of the diagonal, got through Pythagoras' Theorem.
appx. 30' 4.9"
If you know its dimensions then use Pythagoras' theorem to find the length of its diagonals.
The diagonal of a square = the length of one side x the square root of 2 (approx 1.414)
d=x√2 where d is a diagonal and x is a side d=80√2 (or 113.137)