46
You can't tell. There are an infinite number of sets of length and width that havea diagonal of 46.The only thing we know for sure is that whatever they are, the square of the lengthand the square of the width add up to 2,116.
A Square 28 by 36 - surely that is a rectangle Use Pythagoras' theorem: 282+362 = 2080 and the square root of this number is 45.607017 or about 46 units
Your question is vague. If by "distance" you mean the diagonal length then on a 46" TV the diagonal length is 45.9". If you mean how far should you sit from a 46" TV then around 7 to 8 feet.
46 sides 3 * 12 + 10
46
You can't tell. There are an infinite number of sets of length and width that havea diagonal of 46.The only thing we know for sure is that whatever they are, the square of the lengthand the square of the width add up to 2,116.
A Square 28 by 36 - surely that is a rectangle Use Pythagoras' theorem: 282+362 = 2080 and the square root of this number is 45.607017 or about 46 units
Your question is vague. If by "distance" you mean the diagonal length then on a 46" TV the diagonal length is 45.9". If you mean how far should you sit from a 46" TV then around 7 to 8 feet.
46 sides 3 * 12 + 10
The square root of 46 times the square root of 46 = 46
46 square meters is 495.14 square feet.
There are 2,003,760 square feet in 46 acres.
The square root of 46 is: ±6.782329983125268
6.78233......(Square root of 46)
46% of 3600 square feet:= 46% * 3600= 0.46 * 3600= 1,656 square feet
3 - f = 6f + 46+f to both sides-------------------3 = 7f + 46- 46 to both sides--------------------43 = 7f÷7 to both sides--------------------43/7 = f