To find the diagonal of a rectangle, you can use the Pythagorean theorem. The diagonal (d) can be calculated using the formula (d = \sqrt{(length^2 + width^2)}). For a rectangle that is 46 feet by 66 feet, the diagonal is (d = \sqrt{(46^2 + 66^2)} = \sqrt{(2116 + 4356)} = \sqrt{6472} \approx 80.5) feet. Therefore, the diagonal is approximately 80.5 feet long.
The diagonal of a 46' x 46' square is 65.05 feet.
About 28.28 feet.
28 x 46 = 1,288 square feet.
multiple 46 x 30 = 1380 sq feet
Let the length be 2x and the width be x: 2(2x+x) = 66 4x+2x = 66 6x = 66 x = 11 feet length = 22 feet and width = 11 feet
The diagonal of a 46' x 46' square is 65.05 feet.
The diagonal is 69.856 feet.
Diagonal = 36.9 feet
The diagonal of a 30' x 30' square is: 42.43 feet.
2.8284 feet
The diagonal is ~16.97 feet.
66' x 20' = 1,320 square feet.
About 28.28 feet.
3x - 20 = 46 3x = 46 + 20 3x = 66 x = 66/3 x = 22 Therefore, the number is 22! :)
25.6125 (rounded)
46 feet x 34 feet x 20 feet = 31280 Cubic Feet.
28 x 46 = 1,288 square feet.