Q: What is the diagonal of square with a side of 40?

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14 The ratio of the side of a square to the diagonal is 1.4.

side of a square is diagonal / 21/2

The diagonal is 33.941 units.

The length of one side of a square with a 16-centimeter diagonal is: 11.31 cm

The diagonal is 21.21 decimeters.

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As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.

The diagonal of a square is not perpendicular to its side. The diagonal of a square will separate the square into two triangles. The diagonal goes from one corner to the opposite corner. Because it is a square, the diagonal and a side of the square will always form a 45-degree angle.

14 The ratio of the side of a square to the diagonal is 1.4.

The side lengths of a square with a diagonal of 16 is: 11.31.

The diagonal of a square 2.0 meters on a side is: 2.828 meters.

side of a square is diagonal / 21/2

Divide the length of the diagonal of a square by 1.4142 (which is the square root of 2) to find the length of a side. Similarly, to find the length of the diagonal of a square, multiply the length of a side by 1.4142.

Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 = 14² ÷ 2 = 98 units²

Not always, the diagonal can be figured out using the Pythagorean Theorem (a²+b²=c²). Where the diagonal is the hypotenuse (c). By rearranging the Pythagorean Theorem, you can see that the diagonal of a square is always 1.4 times the side of the square.

As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape). If you are referring to a square with an area of 11 square inches then: Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 11 sq in) = √22 in ≈ 4.69 in If you mean an 11 inch square, ie a square with 11 inches along each side: Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 11 in × √2 ≈ 15.6 in

The diagonal is 33.941 units.

Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 36) = 6√2 ≈ 8.49