For solving a quadratic, you mean? Well, if you have real solutions you know that your quadratic has real numbers that make f(x) equal 0. For example, the quadratic f(x) = x^2 - x - 6 has -2 and 3 for solutions, because if you put in either of those two numbers for x, you get 0.
I don't know how far along in your math career you are, but there aren't really any quadratics with no solutions, just with no real solutions. Some quadratics require you to take the square root of a negative number to get a solution, which is acceptable, it's just not a real solution anymore.
Yes, I can't think of any way that a real number minus another real number would be complex or purely imaginary. My answer is yes.
Integer numbers are a subset of real numbers. Real numbers may contain fractions.
A fraction is just a number. It's as real as any whole number (or decimal).
There is no difference between real solutions and real roots.
The graph of imaginary numbers takes two axes. A part for the real part and the i part.
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If you are talking about integers on the number line, the answer is 1. If you are talking about real numbers, then there is always a real number between every other two, so you can't really talk about the difference.
3
Rational numbers are numbers that can be written as a fraction. Real numbers are any number, including irrationals.
Yes, I can't think of any way that a real number minus another real number would be complex or purely imaginary. My answer is yes.
Integer numbers are a subset of real numbers. Real numbers may contain fractions.
A fraction is just a number. It's as real as any whole number (or decimal).
An example of a whole number would be this >>> 2 1/3 Except a real number would be any rational Or irrational number :)
There is no difference between real solutions and real roots.
The graph of imaginary numbers takes two axes. A part for the real part and the i part.
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yes