If you are looking to factor this expression, then it does not have a real solution.
x2 + x2 = 2x2
Yes. Consider x2 ≥ 0
x2+24x+144 = 9 x2+24x+144-9 = 0 x2+24x+135 = 0 (x+9)(x+15) = 0 x = -9 or x = -15
2 log(x) = log(8)log(x2) = log(8)x2 = 8x = sqrt(8) = 2.82843 (rounded)Note that only the positive square root of 8 can serve as a solution to thegiven equation, since there's no such thing as the log of a negative number.
The answer is 8.5, which is one solution and real.
x2≤64
x2 ≥ 0 is one possible answer.
There are no real solutions to this equation because you cannot take the square root of a negative number. However,x2 + 4 = 0x2 = -4sqrt(x2) = sqrt(-4)x = 2i, -2ihere are the imaginary solutions.
x2 + 49 = 0 ∴ x2 = -49 ∴ x = 7i
-4 and 4
I'll show work. X2-8x-4=0. X2-8x=4. X-8x=2. -7x=2. X=-(2/7).
find number of integer solution of X1+x2+x3=24
The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)
You should be able to look at this equation, or use the discriminant and know that there are no real roots.
x = { +6, -6 }
x2 23x equals 0