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What is the distance between the points -1 1 and 1 -1?
The distance between the points can be calculated by using the difference in the x coordinates, the difference in the y coordinates and Pythagoras. distance = sqrt((difference_in_x_coords)2 + difference_in_y_coords)2) So for the points (-1, 1) and (1, -1) the distance between them is: sqrt((-1 - 1)2 + (1 - -1)2) =sqrt(22 + 22) =sqrt(4 + 4) = sqrt(8) ~= 2.83
What is the slope of the line that contains the points (-4 2) and (2 3)?
Just divide (difference in y-coordinates) by (difference in x-coordinates). In this case, the calculation is:(-4 - 2) / (2 - 3) Or equivalently: (2 - (-4)) / (3 - 2) In other words, the order of the points doesn't matter.
What is the distance between the points 4 and 1 and -3 and 6?
The distance between these two points is 8.6. I found this by finding the difference between the two x values and the difference of the two y values. The difference between the x value was found like this: 4- (-3)= 7 and the difference between the y values was found the same way: 1-6=-5. Now to find the length between the two points, you need to use Pythagorean theorem because a right angle triangle is created with the difference between the two x values and the difference between the two y values. Lets call the length between these two points r. The formula to find r would be r^2= x^2 + y^2. r^2= (7)^2 + (-5)^2 r^2= 49 + 25 r^2= 74 r= square root of 74 r=8.6 You square root 74 because to get r by itself you have to square root r to get rid of the exponent.
What is the slope of (0 -4) and (3 2)?
To calculate the slope of a line that goes between two points, you need to divide the difference in y-coordinates, by the difference in x-coordinates. In this case, hte calculation would be: (2 - (-4)) / (3 - 0)
What is the slope of the line that passes through the points -2 2 and -4 -2?
Use the definition of the slope, as (difference in y) / (difference in x).
