The difference in resistance between two points, p and q, typically refers to the electrical resistance encountered when current flows between these points in a circuit. This resistance can be affected by factors such as the material properties, length, cross-sectional area of the conductor, and temperature. If p and q are part of a circuit, the resistance can be calculated using Ohm's Law (R = V/I), where R is resistance, V is voltage, and I is current. The total resistance between p and q may also depend on how other resistive components are arranged in the circuit (series or parallel).
No, the statement "not(p and q)" is not equal to "(not p) or q." According to De Morgan's laws, "not(p and q)" is equivalent to "not p or not q." This means that if either p is false or q is false (or both), the expression "not(p and q)" will be true. Therefore, the two expressions represent different logical conditions.
Only if p and q are DIFFERENT primes.
A rational number can be expressed as a ratio in the form, p/q, where p and q are integers and q > 0.
The sum of p and q means (p+q). The difference of p and q means (p-q).
Yes. Any number of the form p/q in which 0 < p < q will do.
If B is between P and Q, then: P<B<Q
In the statement "p implies q," the relationship between p and q is that if p is true, then q must also be true.
Theory: - Kelvin's bridge is a modification of whetstone's bridge and always used in measurement of low resistance. It uses two sets of ratio arms and the four terminal resistances for the low resistance consider the ckt. As shown in fig. The first set of ratio P and Q. The second set of ratio arms are p and q is used to connected to galvanometer to a pt d at an Approx. potential between points m and n to eliminate the effects of connecting lead of resistance r between the known std. resistance 's' and unknown resistance R .The ratio P/Q is made equal to p/q. under balanced condition there is no current flowing through galvanometer which means voltage drop between a and b, Eab equal to the voltage drop between a and c, Eamd. Now Ead=P/P+Q ; Eab=I[R+S+[(p+q)r/p+q+r]] ------------(1) Eamd= I[R+ p/p+q[ (p+q)r/p+q+r]] ---------------------(2) For zero deflection->Eac=Ead [ P/P+Q]I[R+S+{(p+q)r/p+q+r}]=I[R+pr/p+q+r] ----(3) Now, if P/Q=p/q Then equation… (3) becomes R=P/Q=S ------------------------------------------------------(4) Equation (4) is the usual working equation. For the Kelvin's Double Bridge .It indicates the resistance of connecting lead r. It has no effect on measurement provided that the two sets of ratio arms have equal ratios. Equation (3) is useful however as it shows the error that is introduced in case the ratios are not exactly equal. It indicates that it is desirable to keep r as small as possible in order to minimize the error in case there is a diff. between the ratio P/Q and p/q. R=P/QS
Ifp < q and q < r, what is the relationship between the values p and r? ________________p
No, it is not valid because there is no operator between P and q.
p=q
there are 32 types of thesis statements possible
Only if p and q are DIFFERENT primes.
The relational operators: ==, !=, =.p == q; // evaluates true if the value of p and q are equal, false otherwise.p != q; // evaluates true of the value of p and q are not equal, false otherwise.p < q; // evaluates true if the value of p is less than q, false otherwise.p q; // evaluates true if the value of p is greater than q, false otherwise.p >= q; // evaluates true of the value of p is greater than or equal to q, false otherwiseNote that all of these expressions can be expressed logically in terms of the less than operator alone:p == q is the same as NOT (p < q) AND NOT (q < p)p != q is the same as (p < q) OR (q < p)p < q is the same as p < q (obviously)p q is the same as (q < p)p >= q is the same as NOT (p < q)
If M P and Q are collinear and MP plus PQ equals MQ then P is between M and Q.
Converse: If p r then p q and q rContrapositive: If not p r then not (p q and q r) = If not p r then not p q or not q r Inverse: If not p q and q r then not p r = If not p q or not q r then not p r
The statement "P and Q implies not not P or R if and only if Q" can be expressed in logical terms as ( (P \land Q) \implies (\neg \neg P \lor R) \iff Q ). This can be simplified, as (\neg \neg P) is equivalent to (P), leading to ( (P \land Q) \implies (P \lor R) \iff Q ). The implication essentially states that if both (P) and (Q) are true, then either (P) or (R) must also hold true, and this equivalence holds true only if (Q) is true. The overall expression reflects a relationship between the truth values of (P), (Q), and (R).