P = 2l + 2w
l = 2w + 8
P = 136
136 = 2l + 2w
136 = 2(2w+8) + 2w
136 = 4w + 16 + 2w
136 = 6w + 16
120 = 6w
w = 20
l = 2(20) + 8
l = 40 + 8
l = 48
CHECK:
136 = 2l + 2w
136 = 2(48) + 2(20)
136 = 96 + 40
136 = 136
If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)
4cm by 13cm
The dimensions of the rectangle are 21 units by 9 units
15m wide and 31m long
Perimeter of a rectangle = twice (length + width), in this case 22 m.
If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)
24m x 34m
4cm by 13cm
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The dimensions of the rectangle are 21 units by 9 units
The dimensions work out as length 15 units and width 8 units Check: 2*(15+8) = 46 units which is its perimeter
twice length + twice width = perimeter In this example, L= 3W 2(3W)+2(W)=64 8W=64 W=6 L =3W L=18 The dimensions of this rectangle are: 18 by 6
15m wide and 31m long
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
Perimeter of a rectangle = twice (length + width), in this case 22 m.
The area is 72 The dimensions would be 6x12 6 * 2 + 12 * 2 = 36