It works out as 2
It is the square root of (-4-11)2+(17-17)2 which works out as 15.
The answer depends on the metric used. The Euclidean distance is sqrt[(-3-4)2 + (5+6)2] = sqrt[72 + 112] =sqrt(49 + 121) = sqrt(170) = 13.0384 (to 6 sf). The Minkowsky distance, on the other hand, is |-3-4| + |5+6| = 7 + 11 = 18. There are other metrics.
-5x + 2y = 11 Cover up the x: 2y = 11 so that y = 11/2 or 5.5 Mark up the point P = (0, 5.5) on the coordinate plane. Cover up the y: -5x = 11 so that x = -11/5 or -2.2 Mark up the point Q = (-2.2, 0) on the coordinate plane. Join PQ and extend in both directions.
20
15
It is the square root of (-4-11)2+(17-17)2 which works out as 15.
If you mean points of (1, -2) and (-9, 3) then the distance is about 11 units using the distance formula
Coordinate: (11, 17)If: 3x+4y-63.5 = 0Then: 4y = -3x+63.5 => y = -3/4x+15.875Slope: -3/4Perpendicular slope: 4/3Perpendicular equation: y-17 = 4/3(x-11) => 3y = 4x+7Both equations intersect at: (6.5, 11)Perpendicular distance: square root of [(6.5-11)^2+(11-17)^2] = 7.5
The answer depends on the metric used. The Euclidean distance is sqrt[(-3-4)2 + (5+6)2] = sqrt[72 + 112] =sqrt(49 + 121) = sqrt(170) = 13.0384 (to 6 sf). The Minkowsky distance, on the other hand, is |-3-4| + |5+6| = 7 + 11 = 18. There are other metrics.
-5x + 2y = 11 Cover up the x: 2y = 11 so that y = 11/2 or 5.5 Mark up the point P = (0, 5.5) on the coordinate plane. Cover up the y: -5x = 11 so that x = -11/5 or -2.2 Mark up the point Q = (-2.2, 0) on the coordinate plane. Join PQ and extend in both directions.
It is 51 - (-11) = 62.
The distance between these two places is 11 miles. This distance is only approximate. This is not the exact distance.
20
11 miles
11 miles
15
11