It works out as 2
It is the square root of (-4-11)2+(17-17)2 which works out as 15.
To find the distance between the points (5, 35) and (11, 43) in the xy-plane, you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the values, we get ( d = \sqrt{(11 - 5)^2 + (43 - 35)^2} = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 ). Therefore, the distance between the two points is 10 units.
The answer depends on the metric used. The Euclidean distance is sqrt[(-3-4)2 + (5+6)2] = sqrt[72 + 112] =sqrt(49 + 121) = sqrt(170) = 13.0384 (to 6 sf). The Minkowsky distance, on the other hand, is |-3-4| + |5+6| = 7 + 11 = 18. There are other metrics.
-5x + 2y = 11 Cover up the x: 2y = 11 so that y = 11/2 or 5.5 Mark up the point P = (0, 5.5) on the coordinate plane. Cover up the y: -5x = 11 so that x = -11/5 or -2.2 Mark up the point Q = (-2.2, 0) on the coordinate plane. Join PQ and extend in both directions.
20
It is the square root of (-4-11)2+(17-17)2 which works out as 15.
If you mean points of (1, -2) and (-9, 3) then the distance is about 11 units using the distance formula
To find the distance between the points (5, 35) and (11, 43) in the xy-plane, you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the values, we get ( d = \sqrt{(11 - 5)^2 + (43 - 35)^2} = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 ). Therefore, the distance between the two points is 10 units.
Coordinate: (11, 17)If: 3x+4y-63.5 = 0Then: 4y = -3x+63.5 => y = -3/4x+15.875Slope: -3/4Perpendicular slope: 4/3Perpendicular equation: y-17 = 4/3(x-11) => 3y = 4x+7Both equations intersect at: (6.5, 11)Perpendicular distance: square root of [(6.5-11)^2+(11-17)^2] = 7.5
The answer depends on the metric used. The Euclidean distance is sqrt[(-3-4)2 + (5+6)2] = sqrt[72 + 112] =sqrt(49 + 121) = sqrt(170) = 13.0384 (to 6 sf). The Minkowsky distance, on the other hand, is |-3-4| + |5+6| = 7 + 11 = 18. There are other metrics.
-5x + 2y = 11 Cover up the x: 2y = 11 so that y = 11/2 or 5.5 Mark up the point P = (0, 5.5) on the coordinate plane. Cover up the y: -5x = 11 so that x = -11/5 or -2.2 Mark up the point Q = (-2.2, 0) on the coordinate plane. Join PQ and extend in both directions.
It is 51 - (-11) = 62.
The distance between these two places is 11 miles. This distance is only approximate. This is not the exact distance.
20
11 miles
The flight distance from Paris, France to Budapest, Hungary is: 778 miles / 1,252 km
11 miles