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What is the distance between -3 and 0?
There is a distance of 3 between -3 and 0.
What is the distance between the origin of a Cartesian coordinate system and the point -6 7?
Using the Law of Pythagoras, you get square root of (62 + 72).The distance between the origin and the point ( -6, 7 ) is ~9.22To find the distance, we use the distance formula.c2 = a2 + b2This is an adaptation from the Pythagorean theorem. In this case, a is the difference in x coordinates; b the difference in y.The Cartesian origin is at ( 0, 0 ). So...c2 = ( -6 - 0 )2 + ( 7 - 0 )2c2 = -62 + 72c2 = 36 + 49c2 = 85c =~ 9.22
How do you simplify a2 plus 7a-8a2 equals 6a7?
a2 + 7a - 8a2 = 6a7 ∴ a2 + 7a - 8a2- 6a7 = 0 ∴ a + 7 - 8a - 6a6 = 0 ∴ 7 - 7a - 6a6 = 0 ∴ 6a6 + 7a - 7 = 0
Design a combinational circuit that accepts a 3 bit number and generates a 6 bit binary number equal to the square of the input number?
Let the inputs be A2 A1 A0 & outputs be S5 S4 S3 S2 S1 S0. Now, make a truth table as follows A2 A1 A0 S5 S4 S3 S2 S1 S0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 1 0 0 0 0 1 0 0 and so on....... Finally we'll get S0 = A0 S1 = 0 S2 = A1 A2(bar) S3 = A0 [ A1 XOR A2] S4 = A2 [A1(bar) + A0 ] S5 = A1 A2
What is the distance between a point and a line containing this point?
The distance is 0.
What is the distance between -3 and 0?
There is a distance of 3 between -3 and 0.
What is the distance between the z-intercept from the x intercept in the equation ax plus by plus cz plus d equals 0?
ax + by + cz + d = 0At the z-intercept, 'x' and 'y' are both zero.cz + d = 0 --> z = -d/c --> The z-intercept is the point (0, 0, -d/c).At the x-intercept, 'y' and 'z' are zero.ax + d = 0 --> x = -d/a --> The x-intercept is the point (-d/a, 0, 0).The distance between the points (0, 0, -d/c) and (-d/a, 0, 0) issqrt[ (-d/a)2 + (-d/c)2 ] = sqrt (d2/a2 + d2/c2) = d sqrt(1/a2 + 1/c2)
What is the distance between the origin of a Cartesian coordinate system and the point -6 7?
Using the Law of Pythagoras, you get square root of (62 + 72).The distance between the origin and the point ( -6, 7 ) is ~9.22To find the distance, we use the distance formula.c2 = a2 + b2This is an adaptation from the Pythagorean theorem. In this case, a is the difference in x coordinates; b the difference in y.The Cartesian origin is at ( 0, 0 ). So...c2 = ( -6 - 0 )2 + ( 7 - 0 )2c2 = -62 + 72c2 = 36 + 49c2 = 85c =~ 9.22
How do you calculate in Excel commission of 7 percent on all sales that are at least 25 percent above cost?
Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )
How do you simplify a2 plus 7a-8a2 equals 6a7?
a2 + 7a - 8a2 = 6a7 ∴ a2 + 7a - 8a2- 6a7 = 0 ∴ a + 7 - 8a - 6a6 = 0 ∴ 7 - 7a - 6a6 = 0 ∴ 6a6 + 7a - 7 = 0
Design a combinational circuit that accepts a 3 bit number and generates a 6 bit binary number equal to the square of the input number?
Let the inputs be A2 A1 A0 & outputs be S5 S4 S3 S2 S1 S0. Now, make a truth table as follows A2 A1 A0 S5 S4 S3 S2 S1 S0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 1 0 0 0 0 1 0 0 and so on....... Finally we'll get S0 = A0 S1 = 0 S2 = A1 A2(bar) S3 = A0 [ A1 XOR A2] S4 = A2 [A1(bar) + A0 ] S5 = A1 A2
If a2 plus b2 plus c2 - ab - bc - ca equals 0 then prove a equals b equals c?
a2 + b2 + c2 - ab - bc - ca = 0 => 2a2 + 2b2 + 2c2 - 2ab - 2bc - 2ca = 0 Rearranging, a2 - 2ab + b2 + b2 - 2bc + c2 + c2 - 2ca + a2 = 0 => (a2 - 2ab + b2) + (b2 - 2bc + c2) + (c2 - 2ca + a2) = 0 or (a - b)2 + (b - c)2 + (c - a)2 = 0 so a - b = 0, b - c = 0 and c - a = 0 (since each square is >=0) that is, a = b = c
What is the distance between a point and a line containing this point?
The distance is 0.
What is the distance between 7.75 and 7.75 on a number line?
The distance is 0.
What is the distance between the origin and the point (5 12)?
Distance from (0, 0) to (5, 12) using distance formula is 13
What is the distance between 5.75 and 0?
5.75
What is the distance between -4 and 0?
4.
