Dist2 = [2 - (-5)]2 + [7 - 0]2 = 72 + 72 = 2*72
So dist = 7*sqrt(2) = 9.8995
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There is a distance of 3 between -3 and 0.
Using the Law of Pythagoras, you get square root of (62 + 72).The distance between the origin and the point ( -6, 7 ) is ~9.22To find the distance, we use the distance formula.c2 = a2 + b2This is an adaptation from the Pythagorean theorem. In this case, a is the difference in x coordinates; b the difference in y.The Cartesian origin is at ( 0, 0 ). So...c2 = ( -6 - 0 )2 + ( 7 - 0 )2c2 = -62 + 72c2 = 36 + 49c2 = 85c =~ 9.22
a2 + 7a - 8a2 = 6a7 ∴ a2 + 7a - 8a2- 6a7 = 0 ∴ a + 7 - 8a - 6a6 = 0 ∴ 7 - 7a - 6a6 = 0 ∴ 6a6 + 7a - 7 = 0
The distance is 0.
The distance is 0.