Q: What is the distance between -4 and 0?

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5 is.

It is the square root of (-3-0)2+(-4-0)2 = 5

-2 & 5

Distance between (0,0) and (8,2): √((8-0)2+(2-0)2) = √(82+22) = √(64+4) = √(68) = 2√17 ~= 8.246

All three numbers would lie between 0 and 1 and, measuring from 0,0.3 would be 3/10 of the distance between 0 and 1,0.16 would be 16/100 = 4/25 of the distance between 0 and 1,0.25 would be 25/100 = 1/4 of the distance between 0 and 1.

Related questions

The distance between the points of (4, 3) and (0, 3) is 4 units

1

Points: (2, 4) and (5, 0) Distance: 5

Since they are the same point, the distance between them is 0.

(0, 4) and (- 4, 6) ???Distance = sqrt[(Y2 - Y1)2 + (X2 - X1 )2]Distance = sqrt[(6 - 4)2 + (- 4 - 0)2]Distance = sqrt( 4 + 16)Distance = sqrt(20)==============

5 is.

The distance between the points of (4, 3) and (0, 3) is 4 units

Distance = sqrt [(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt [(6 - 4)2 + (- 4 - 0)2]Distance = sqrt [(2)2 + (- 4)2]Distance = sqrt(4 + 16)Distance = sqrt(20)==============

It is the square root of (-3-0)2+(-4-0)2 = 5

-2 & 5

It is the square root of (-3-0)2+(-4-0)2 = 5

Distance between (0,0) and (8,2): √((8-0)2+(2-0)2) = √(82+22) = √(64+4) = √(68) = 2√17 ~= 8.246