The distance is 4
It is the square root of (-6-4)2+(1-3)2 = 2 times sq rt of 26 or about 10.198 to 3 decimal places
If you mean (4, 5) and (10, 13) then the distance is 10
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
Since they are the same point, the distance between them is 0.
If you mean points of (5, 5) and (1, 5) then the distance is 4
What is the distance between (4, -2) and (-1,6)?
What is the distance between (4, -2) and (-1,6)?
The distance is 4
What is the distance between (4, -2) and (-1,6)?
3-4 = -1 -21 the distance between -1 and -21 is -20 -20 -1 = -21
4
It is the square root of (-6-4)2+(1-3)2 = 2 times sq rt of 26 or about 10.198 to 3 decimal places
Points: (23, -33) and (4, 9) Distance: square root of 2125 which is about 46
Using the distance formula from (3, 1) to (7, 1) is 4 units
If you mean (4, 5) and (10, 13) then the distance is 10