The distance is 5. The x distance is 3, the y distance is 4, and the diagonal is
sqrt(32 + 42) = sqrt (9 + 16) = sqrt 25 = 5
The line ( y = 3 ) is a horizontal line. The distance from the point ( (5, 4) ) to this line can be found by calculating the vertical distance between the point and the line. Since the y-coordinate of the point is 4 and the line is at ( y = 3 ), the distance is ( |4 - 3| = 1 ). Therefore, the distance from the point ( (5, 4) ) to the line ( y = 3 ) is 1 unit.
To find point A', which is the transformed point, you first determine the distance from point A (3, 4) to the line x = 2. The distance is the horizontal distance, which is |3 - 2| = 1 unit. Since point A' must be the same distance from the line, it can be located either at (1, 4) or (5, 4), depending on whether it is to the left or right of the line x = 2.
It is the square root of (-6-4)2+(1-3)2 = 2 times sq rt of 26 or about 10.198 to 3 decimal places
If you mean (4, 5) and (10, 13) then the distance is 10
Using the number line ;- ...-5,-4,-3,-2,-1,0,1,2,3,4,5 .... Starting at '-3' and moving to the right to '1'. we make '4' steps/ So the distance is '4'. !!!!
The line ( y = 3 ) is a horizontal line. The distance from the point ( (5, 4) ) to this line can be found by calculating the vertical distance between the point and the line. Since the y-coordinate of the point is 4 and the line is at ( y = 3 ), the distance is ( |4 - 3| = 1 ). Therefore, the distance from the point ( (5, 4) ) to the line ( y = 3 ) is 1 unit.
Since they are the same point, the distance between them is 0.
If you mean points of (5, 5) and (1, 5) then the distance is 4
What is the distance between (4, -2) and (-1,6)?
What is the distance between (4, -2) and (-1,6)?
What is the distance between (4, -2) and (-1,6)?
4
3-4 = -1 -21 the distance between -1 and -21 is -20 -20 -1 = -21
It is the square root of (-6-4)2+(1-3)2 = 2 times sq rt of 26 or about 10.198 to 3 decimal places
Points: (23, -33) and (4, 9) Distance: square root of 2125 which is about 46
The distance between the starting point and the destination is 80.1km, (49.8mi), and with reasonable traffic conditions it will take approximately 1 hour 4 minutes of driving time.
Using the distance formula from (3, 1) to (7, 1) is 4 units