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d = Root of((y" - y')2 + (x" - x')2)

d = Root of ((30-8)2 + (21-3)2)

d = Root of (22x22 + 18x18)

d = Root of (484 + 324)

d = Root of 808 = 28.425

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What is the distance between 21 -30 and 3 8?

Points: (21, -30) and (3, 8) Distance: (21-3)2+(-30-3)2 = 1413 and the square root of this is the distance which is about 37.589 to 3 decimal places


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To find the distance between the points (21, -30) and (3, 8), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have: [ d = \sqrt{(3 - 21)^2 + (8 - (-30))^2} = \sqrt{(-18)^2 + (38)^2} = \sqrt{324 + 1444} = \sqrt{1768} \approx 42.03 ] Thus, the distance between the points is approximately 42.03.


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