Points: (6, 5) and (30, 15)
Distance: 26 by using the distance formula
15
26
The distance between two numbers on a number line is calculated by taking the absolute difference between the two numbers. In this case, the absolute difference between 15 and 64 is |15 - 64| = 49. Therefore, the distance between 15 and 64 is 49 units.
If you mean points of (-6, 3) and (6, -6) then the distance works out as 15
It is the square root of (-4-11)2+(17-17)2 which works out as 15.
Distance between the points of (3, 7) and (15, 16) is 15 units
The distance works out as 22 between the points of (15, -17) and (-7, -17)
the first point is x = 28 and y = -17. The second point is x = -15 and y = -17. Since both points have the same y coordinate then the points are on a straight horizontal line and distance is the difference of the x coordinates, or 28 - (-15) = 43
To find the distance between two points (x0, y0) and (x1, y1) use Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((8 - -7)² + (-5 - -13)²) → distance = √(15² + 8²) → distance = √289 → distance = 17 units.
26
15
10
The distance between two numbers on a number line is calculated by taking the absolute difference between the two numbers. In this case, the absolute difference between 15 and 64 is |15 - 64| = 49. Therefore, the distance between 15 and 64 is 49 units.
If you mean points of (-6, 3) and (6, -6) then the distance works out as 15
It is the square root of (-4-11)2+(17-17)2 which works out as 15.
the distance between the two areas is about 15 minutes apart in a car.
there is 34 miles distance between the two