15
26
If you mean points of (-6, 3) and (6, -6) then the distance works out as 15
It is the square root of (-4-11)2+(17-17)2 which works out as 15.
13 The distance between 2 points in a cordinate space is SQRT ((x2 -x1)2 + (y2- y1)2) Hence the answer to your question would be square root of (1-(-4))2 + (3-15)2 which would be square root of (25 + 144) or square root of (169) which is nothing but 13!!!
Distance between the points of (3, 7) and (15, 16) is 15 units
The distance works out as 22 between the points of (15, -17) and (-7, -17)
To find the distance between two points (x0, y0) and (x1, y1) use Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((8 - -7)² + (-5 - -13)²) → distance = √(15² + 8²) → distance = √289 → distance = 17 units.
15
26
10
If you mean points of (-6, 3) and (6, -6) then the distance works out as 15
It is the square root of (-4-11)2+(17-17)2 which works out as 15.
the distance between the two areas is about 15 minutes apart in a car.
To find the distance between any two points on the Cartesian plane use Pythagoras: The distance between (x0, y0) and (x1, y1) is given by: distance = √((x1 - x0)² + (y1 - y0)²) → distance between (28, -17) and (-15, -17) is: distance = √((x1 - x0)² + (y1 - y0)²) = √((-15 - 28)² + (-17 - -17)²) = √((-43)² + (0)) = √1849 = 43 ------------------------ In this case, the y-coordinates are the same (y0 = y1 = -17), so this becomes: distance = √((x1 - x0)² + (y0 - y0)²) = √((x1 - x0)² + 0²) = √((x1 - x0)²) = |x1 - x0| The vertical bars around the expression mean the absolute value of the expression, which is the numerical value of the expression ignoring the sign. distance = |x1 - x0| = |-15 - 28| = |-43| = 43.
there is 34 miles distance between the two
the first point is x = 28 and y = -17. The second point is x = -15 and y = -17. Since both points have the same y coordinate then the points are on a straight horizontal line and distance is the difference of the x coordinates, or 28 - (-15) = 43