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A train starting from rest attains a velocity of 72Km hr in 5 minutes. Assuming that the acceleration is uniform what is the distance travel by train while attained the velocity?
As the acceleration is uniform, the train has an average speed that is half the difference between the start and final velocities, which in this case is half the final velocity. 1 hr = 60 min 1 km/h = 1 km ÷ 1 hr = km ÷ 60 min = 1/60 km/min Distance = velocity × time = (½ × 72 × 1/60 km/min) × (5 min) = 36/60 × 5 km = 3 km
True or false a velocity of 50 rad per min is a linear velocity?
False.
What is the trigonometric formula for rotational velocity?
Velocity = Radius x RPM For example if a body of 32 Inches in diameter rotating at 3600 rpm, the velocity is calculated by Velocity = 32/2 * 3600 Velocity = 57,200 inches per minute Velocity = 57,200 Inches/min * 60 Min/Hr * 1ft/12in * 1 mi/5280 ft Velocity = 54.5 miles per hr
How do you calculate initial velocity with time and absorbance as the variables?
Convert the velocity Vmax from ΔA/min to nmol/min (milliunits, mU). For example: 1 Unit = 1 U = 1 μmol PNP formed per min 1 milli-Unit = 1 mU = 1 nmol PNP formed per min Extinction coefficient ε for PNP at 410 nm = 15,000 M-1 cm-1 And the pathlength = 0.34 cm if the velocity v is determined to be 0.294 ∆A/min (absorbance units per min), then: 0.294 ∆A /min * M/(15,000 A * 0.34 cm) = 0.0000196 M/min = 19.6 μM/min = = 19.6 μmol / (liter * min) = 0.0196 μmol / (ml * min) The enzymatic reaction was carried out in 250 μl solution, hence the velocity of the enzyme is 0.0196 μmol / (ml * min) * 0.25 ml = 0.0049 μmol/min = 4.9 nmol/min PNP generated. v = 4.9 nmol/min = 4.9 mU
Velocity of a car that travels 80 km in 38 min convert to meters and seconds?
distance = rate * time 80 km = r * 38 minute r = 80 km / 38 min * 1000 m/km * 60 seconds/minute = 4800000/38 ~= 126315.79 m/s
