Since you can't take the square root of a negative number, the expression under the square root must be equal to, or greater than, zero. Just solve this inequality, with the expression under the square root.
If I understand correctly, the expression under the root is 9x2-4. For the inequality, get the critical points through an equation first: 9x2-4 = 0; 9x2 = 4; x2 = 4/9; x = plus-or-minus 2/3. Analyzing any points to the left of -2/3, between -2/3 and 2/3, and to the right of 2/3, you quickly see that the inequality is fulfilled for any number that is either <= -2/3, or >= 2/3.
Domain is greater than or equal to zero. same with range
No, id does not.
The square root of 1753 equals 2,315.0324(rounded).
That would be a number to the 6th power, like 64.
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what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
Domain is greater than or equal to zero. same with range
No, id does not.
The square root of 1753 equals 2,315.0324(rounded).
The square root of 2 raised to the fifth power equals 5.65685424949
The number that, when raised to the power of 2, equals 128 is the square root of 128. The square root of 128 is approximately 11.31. Therefore, 11.31 raised to the power of 2 equals 128.
That would be a number to the 6th power, like 64.
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y=(√1)-x2 The domain is the set of numbers that "x" can be. In this equation "x" can be any real number. The domain for this problem would be (-inf,inf) *Inf= Infinity*
rearrange the following: A^(1/n)= the nth root of A. eg A to the power 1/2 equals the square root of A. A to the power 1/3 equals the cube root of A. etc.
Square root of 6.25 equals ± 2.5
square root of x = 3 Since the square root of a number is basically that number to the power of 1/2, if you square both sides it will cancel out the square root.(x1/2)2 = 32x = 32x = 9Since 3 squared is 9, x equals 9.