It is -12.8, -6.4, 0, 6.4 and 12.8
It is difficult to say because of uncertainty as to what xx-4 represents. x2 - 4 = 4 gives x2 = 8 so x = ± 2*sqrt(2)
If it were written in a book of some sort, fx or f(x) is read aloud as "f or x". "f" is a function of some variable, "x". By function it means something happens to x e.g. x2 or 3x+4.
yes. it is a function
It depends on the domain but, if the domain is the real numbers, so is the range.
The graph of the function f(x) = 4, is the horizontal line to the x=axis, which passes through (0, 4). The domain of f is all real numbers, and the range is 4.
It is -12.8, -6.4, 0, 6.4 and 12.8
The domain of the function 1/2x is {0, 2, 4}. What is the range of the function?
The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
It is difficult to say because of uncertainty as to what xx-4 represents. x2 - 4 = 4 gives x2 = 8 so x = ± 2*sqrt(2)
please elaborate your question
y = 4(2x) is an exponential function. Domain: (-∞, ∞) Range: (0, ∞) Horizontal asymptote: x-axis or y = 0 The graph cuts the y-axis at (0, 4)
x = ¼x^4 + 4x + k where k can be any number
If it were written in a book of some sort, fx or f(x) is read aloud as "f or x". "f" is a function of some variable, "x". By function it means something happens to x e.g. x2 or 3x+4.
yes. it is a function
Interpreting the question as "evaluate f(x) = -x2 + 5 for x = 4". This is the same as asking "what is f(4)". To evaluate f(4) just replace each instance of the x in the definition of f(x) by the number 4: f(4) = -42 + 5. The result is -11.
It depends on the domain but, if the domain is the real numbers, so is the range.