Q: What is the equation for a circle with a center of 1 1 and a radius of 1?

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This makes no sence

The equation is: (x+1)^2 +(y+5)^2 = 36

(x - 1)2 + (y + 1)2 = 1

(x-3)2 + (y-1)2 = 42

(x + 1)2 + (y + 5)2 = 36

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This makes no sence

If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4

If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4

A unit circle is a circle of radius 1. If it's center is at the origin of an xy-coordinate system, then the equation is x (squared) + y (squared) = 1

The equation is: (x+1)^2 +(y+5)^2 = 36

(x - 1)2 + (y + 1)2 = 1

(x + 2)2 + (y - 2)2 = 1

(x + 2)2 + (y - 2)2 = 1

It is (x - 1)^2 + (y - 1)^2 = 5^2

It is: (x+3)^2+(y-1)^2 = 25

(x + 1)2 + (y + 5)2 = 36

(x-3)2 + (y-1)2 = 42