(x + 2)2 + (y - 2)2 = 1
A unit circle is a circle of radius 1. If it's center is at the origin of an xy-coordinate system, then the equation is x (squared) + y (squared) = 1
(x + 2)2 + (y - 2)2 = 1
The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1
Equation: (x+1)^2 +(y-3)^2 = 16
Equation of circle: x^2 +y^2 -6x +4y +5 = 0 Completing the squares: (x-3)^2 +(y+2)^2 = 8 Radius of circle: square root of 8 Center of circle: (3, -2) Circle makes contact with the x axis at: (1, 0) and (5, 0) Slope of 1st tangent: 1 Slope of 2nd tangent: -1 1st tangent line equation: y = 1(x-1) => y = x-1 2nd tangent line equation: y = -1(x-5) => y = -x+5
3.14 x 1
This makes no sence
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
A unit circle is a circle of radius 1. If it's center is at the origin of an xy-coordinate system, then the equation is x (squared) + y (squared) = 1
The equation is: (x+1)^2 +(y+5)^2 = 36
(x - 1)2 + (y + 1)2 = 1
(x + 2)2 + (y - 2)2 = 1
It is (x - 1)^2 + (y - 1)^2 = 5^2
(x + 1)2 + (y + 5)2 = 36
(x-3)2 + (y-1)2 = 42
It is: (x+3)^2+(y-1)^2 = 25