Points: (0, -2) and (20, 42) Slope: 11/5 Equation: 5y = 11x-10 or as y = 2.2x-2.
Here is the information you are given and a corresponding equation demonstrating the relationship between the given information and the unknown. Vtotal = Vwater + Vsand = 42cm3 Here is the given equation rearranged (by subtracting the volume of water from both sides) to target the unknown information (volume of sand). Vsand = Vtotal - Vwater Plugging in the given info to the equation yields your answer. Vsand = 42 - 20 Vsand = 22cm3
If you mean points of (2, -3) and (4, 2) then the slope is 5/2 and the straight line equation is 2y = 5x-16
There needs to be an x variable to create a graph.
86 - 42 = 44
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
Points: (0, -2) and (20, 42) Slope: 11/5 Equation: 5y = 11x-10 or as y = 2.2x-2.
1 cubic foot = 1,728 cubic inches1 gallon = 231 cubic inches42 gallons = (42 x 231) cubic inches = (42 x 231 / 1,728) = 5.6146 cubic feet (rounded)
42 gallons (US) is equal to: 5.615 cubic feet.
42
Here is the information you are given and a corresponding equation demonstrating the relationship between the given information and the unknown. Vtotal = Vwater + Vsand = 42cm3 Here is the given equation rearranged (by subtracting the volume of water from both sides) to target the unknown information (volume of sand). Vsand = Vtotal - Vwater Plugging in the given info to the equation yields your answer. Vsand = 42 - 20 Vsand = 22cm3
If you mean points of (2, -3) and (4, 2) then the slope is 5/2 and the straight line equation is 2y = 5x-16
There are 0.0011411411411411411 cubic yards in a 39 gallon trash bag.
There needs to be an x variable to create a graph.
There are: 37*42*4 = 6216 cubic inches
86 - 42 = 44
Cubic volume in feet (ft^3) can be calculated by multiplying length (l), width (w) and height (h) by the equation cubic volume (v^3) = l*w*h. The volume in this example would be 102,816 ft^3.