y= ax^3+bx^2+cx-42, assuming the point was (0, 42)
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Points: (0, -2) and (20, 42) Slope: 11/5 Equation: 5y = 11x-10 or as y = 2.2x-2.
Here is the information you are given and a corresponding equation demonstrating the relationship between the given information and the unknown. Vtotal = Vwater + Vsand = 42cm3 Here is the given equation rearranged (by subtracting the volume of water from both sides) to target the unknown information (volume of sand). Vsand = Vtotal - Vwater Plugging in the given info to the equation yields your answer. Vsand = 42 - 20 Vsand = 22cm3
If you mean points of (2, -3) and (4, 2) then the slope is 5/2 and the straight line equation is 2y = 5x-16
There needs to be an x variable to create a graph.
86 - 42 = 44