(y2-y1)=m(x2-x1)
The point-slope form of a line's equation is given by (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is a point on the line. Given the slope (m = -5) and the point ((1, -1)), the equation in point-slope form is (y + 1 = -5(x - 1)).
When it is a line through the origin.
Point-slope form is just another way to express a linear equation. It uses two (any two points that fall on the line) and the slope of the line (Therefore the name point-slope form).y2 - y1 = m(x2 - x1)...with m as the slope.
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
Slope-intercept form (y = mx + b) expresses a linear equation in terms of the slope (m) and the y-intercept (b), making it easy to identify these key features directly from the equation. In contrast, point-slope form (y - y₁ = m(x - x₁)) focuses on a specific point (x₁, y₁) on the line and the slope (m), which is useful for writing the equation when a point and the slope are known. Essentially, slope-intercept form is best for graphing, while point-slope form is ideal for deriving equations from given points.
no it is different
The point-slope form of a line's equation is given by (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is a point on the line. Given the slope (m = -5) and the point ((1, -1)), the equation in point-slope form is (y + 1 = -5(x - 1)).
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Point: (-6, -2) Slope: 5 Equation: y = 5x+28
When it is a line through the origin.
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Point: (1, 4) Slope: -3 Equation: y = -3x+7
Point-slope form is just another way to express a linear equation. It uses two (any two points that fall on the line) and the slope of the line (Therefore the name point-slope form).y2 - y1 = m(x2 - x1)...with m as the slope.
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
You use point-slope form to find the equation of a line if you only have a point and a slope or if you are just given two point. Usually you will convert point-slope form to slope-intercept form to make it easier to use.
Slope: -3 Point: (4, -5) Equation: y = -3x+7
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.