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What is the equation of the line that passes through the point (63) and has a slope of -1 over 3?
If the point is (6, 3) and the slope is -1/3 then the equation works out as 3y = -x+15
What is the point-slope equation of the line with slope three over two that goes through the point -3 5?
It is: y-5 = 1.5(x--3) => y = 1.5x+9.5
Which is an equation for the line that passes through the origin and has a slope of 3 over 5?
If you know that the line passes through the point (0,0) and has a slope of 0.6, then you can use the point-slope formula to find the equation of the line. y - y1 = m(x - x1) becomes y - 0 = 0.6(x - 0) becomes y = 0.6x
What is the equation of the line that passes through the point (-3 1) and has a slope of 2 over 3?
To find the equation of the line that passes through the point (-3, 1) with a slope of ( \frac{2}{3} ), you can use the point-slope form of the linear equation: ( y - y_1 = m(x - x_1) ). Substituting the point (-3, 1) and the slope ( \frac{2}{3} ) into the equation gives: [ y - 1 = \frac{2}{3}(x + 3). ] This simplifies to ( y = \frac{2}{3}x + 3 ).
How do you make and equation on a line in a graph?
The equation for the slope of a linear equation is Y=Mx+b, where m is the slope of the line, (Rise over run) and where B is the Y-intercept. (Where it crosses the Y axis)
What is the equation of the line that passes through the point (63) and has a slope of -1 over 3?
If the point is (6, 3) and the slope is -1/3 then the equation works out as 3y = -x+15
What is the equation of the that line passes through the point 7 -5 and has a slope of -4 over 7?
Point: (7, -5) Slope: -4/7 Equation: 7y = -4x-7
Find equation perpendicular to given line contain given point?
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
What is the equation of the line that passes through the point (6 3) and has a slope of -1 over 3?
A line through point (X, Y) with slope m has equation: y - Y = m(x - X) The line through (6, 3) with slope -1 has equation: y - 3 = -1(x - 6) → y -3 = -x + 6 → y + x = 9
What is the point-slope equation of the line with slope three over two that goes through the point -3 5?
It is: y-5 = 1.5(x--3) => y = 1.5x+9.5
Which is an equation for the line that passes through the origin and has a slope of 3 over 5?
If you know that the line passes through the point (0,0) and has a slope of 0.6, then you can use the point-slope formula to find the equation of the line. y - y1 = m(x - x1) becomes y - 0 = 0.6(x - 0) becomes y = 0.6x
What is the equation of the line that passes through the point (-3 1) and has a slope of 2 over 3?
To find the equation of the line that passes through the point (-3, 1) with a slope of ( \frac{2}{3} ), you can use the point-slope form of the linear equation: ( y - y_1 = m(x - x_1) ). Substituting the point (-3, 1) and the slope ( \frac{2}{3} ) into the equation gives: [ y - 1 = \frac{2}{3}(x + 3). ] This simplifies to ( y = \frac{2}{3}x + 3 ).
Find an equation of the line having the given slope and containing the given point m equals 2 over 3 and 2 and -1?
If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7
How do you make and equation on a line in a graph?
The equation for the slope of a linear equation is Y=Mx+b, where m is the slope of the line, (Rise over run) and where B is the Y-intercept. (Where it crosses the Y axis)
What is the slope of the line given by the equation y 1 over 2 x -9?
slope is 1/2
What is the slope in alegbra?
Slope is the characteristic of a line that gives the relationship between the position of one point on the line and the next point. If given two points it can be found using the formula y sub 2 - y sub 1 over x sub 2 - x sub 1. If you are given an equation in slope intercept form the slope is the value of m. If your are given an equation in standard form the slope is -a/b.In mathematics, the slope or gradient of a line describes its steepness, incline, or grade. A higher slope value indicates a steeper incline.
How do you write an equation of a line given the y-intercept and a point?
y=mx+b, right? So, b is the height of the y-intercept that you already have. M is the slope, rise over run. The slope is the same at all part of a line. You take the distance up from the y-intercept to the point and divide by the distance right from the y-intercept to the point. Replace m with that and you have the equation.
