To find the equation of the line that passes through the points (0, 3) and (6, 2), we first calculate the slope (m) using the formula (m = \frac{y_2 - y_1}{x_2 - x_1}). This gives us (m = \frac{2 - 3}{6 - 0} = \frac{-1}{6}). Using the point-slope form of the equation (y - y_1 = m(x - x_1)) with the point (0, 3), we get (y - 3 = -\frac{1}{6}(x - 0)), which simplifies to (y = -\frac{1}{6}x + 3).
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
414
If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
sda
Assuming the point is (9, -4), the equation is y = -4.
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
The equation is: y = 4x-22
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
414
The equation works out as: y = 5x+7
If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3
"14" is not a point; you need two coordinates to specify a point.
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10
Point: (2, 17)Slope: 7Equation: y = 2x+13