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How do you write an equation in standard form of a circle with a center and radius?
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
How do you Writing the Equation of a Circle in Standard Form?
(x - A)2 + (y - B)2 = R2 The center of the circle is the point (A, B) . The circle's radius is ' R '.
What is the formula for the center of the circle?
The formula for the center of a circle is given by the coordinates ((h, k)) in the standard equation of a circle, which is ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is the radius. If the equation is presented in a different form, you can derive the center by rearranging the equation to match the standard form.
What is the radius for a circle with the equation x2 y2 16?
The equation you provided, ( x^2 + y^2 = 16 ), represents a circle centered at the origin (0,0). To find the radius, you can rewrite the equation in the standard form ( x^2 + y^2 = r^2 ), where ( r ) is the radius. Here, ( r^2 = 16 ), so the radius ( r ) is ( \sqrt{16} = 4 ). Thus, the radius of the circle is 4 units.
What is h in the standard form equation of a circle if the center is at h v and the radius is r?
(x - h)2 + (y - v)2 = r2
How do you write an equation in standard form of a circle with a center and radius?
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
What is the equation of the circle standard form?
Area of a circle = pi*radius squared Circumference of a circle = 2*pi*radius or diameter*pi
How do you Writing the Equation of a Circle in Standard Form?
(x - A)2 + (y - B)2 = R2 The center of the circle is the point (A, B) . The circle's radius is ' R '.
How is the Pythagorean theorem used to develop the equation of a circle in standard form?
The Pythagorean theorem is used to develop the equation of the circle. This is because a triangle can be drawn with the radius and any other adjacent line in the circle.
What is the formula for the center of the circle?
The formula for the center of a circle is given by the coordinates ((h, k)) in the standard equation of a circle, which is ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is the radius. If the equation is presented in a different form, you can derive the center by rearranging the equation to match the standard form.
Which number in the standard equation for a circle centered at the origin should one increase to make the circle larger?
You should increase the radius in the standard equation of a circle centered at the origin. The general form is ( x^2 + y^2 = r^2 ), where ( r ) is the radius. By increasing ( r ), you extend the distance from the center to any point on the circle, making it larger.
What is the radius for a circle with the equation x2 y2 16?
The equation you provided, ( x^2 + y^2 = 16 ), represents a circle centered at the origin (0,0). To find the radius, you can rewrite the equation in the standard form ( x^2 + y^2 = r^2 ), where ( r ) is the radius. Here, ( r^2 = 16 ), so the radius ( r ) is ( \sqrt{16} = 4 ). Thus, the radius of the circle is 4 units.
What is h in the standard form equation of a circle if the center is at h v and the radius is r?
(x - h)2 + (y - v)2 = r2
What is the standard form of the equation of a circle with center (2 3) and radius 4 units?
(x-2)^2 +(y-3)^2 = 16
This circle is centered at the point (4 5) and the length of its radius is 3. What is the equation of the circle?
The equation of a circle can be expressed in the standard form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. For a circle centered at (4, 5) with a radius of 3, the equation becomes ((x - 4)^2 + (y - 5)^2 = 3^2). Therefore, the equation of the circle is ((x - 4)^2 + (y - 5)^2 = 9).
What is the radius of the circle x2 y2 9?
It seems there is a small error in the equation you provided. A standard circle equation is typically in the form ((x - h)^2 + (y - k)^2 = r^2), where ( (h, k) ) is the center and ( r ) is the radius. If you meant ( x^2 + y^2 = 9 ), then the radius of the circle is ( r = \sqrt{9} = 3 ).
This circle is centered at the point (3 2) and the length of its radius is 5. What is the equation of the circle?
The equation of a circle in standard form is given by ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center of the circle and (r) is the radius. For a circle centered at the point (3, 2) with a radius of 5, the equation is ((x - 3)^2 + (y - 2)^2 = 5^2). Simplifying this, we get ((x - 3)^2 + (y - 2)^2 = 25).
