well you would times that by: R2=D*3.14(pie)=C
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
(x - A)2 + (y - B)2 = R2 The center of the circle is the point (A, B) . The circle's radius is ' R '.
The formula for the center of a circle is given by the coordinates ((h, k)) in the standard equation of a circle, which is ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is the radius. If the equation is presented in a different form, you can derive the center by rearranging the equation to match the standard form.
(x - h)2 + (y - v)2 = r2
The equation of a circle can be expressed in the standard form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. For a circle centered at (4, 5) with a radius of 3, the equation becomes ((x - 4)^2 + (y - 5)^2 = 3^2). Therefore, the equation of the circle is ((x - 4)^2 + (y - 5)^2 = 9).
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
Area of a circle = pi*radius squared Circumference of a circle = 2*pi*radius or diameter*pi
(x - A)2 + (y - B)2 = R2 The center of the circle is the point (A, B) . The circle's radius is ' R '.
The Pythagorean theorem is used to develop the equation of the circle. This is because a triangle can be drawn with the radius and any other adjacent line in the circle.
The formula for the center of a circle is given by the coordinates ((h, k)) in the standard equation of a circle, which is ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is the radius. If the equation is presented in a different form, you can derive the center by rearranging the equation to match the standard form.
You should increase the radius in the standard equation of a circle centered at the origin. The general form is ( x^2 + y^2 = r^2 ), where ( r ) is the radius. By increasing ( r ), you extend the distance from the center to any point on the circle, making it larger.
(x - h)2 + (y - v)2 = r2
(x-2)^2 +(y-3)^2 = 16
The equation of a circle can be expressed in the standard form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. For a circle centered at (4, 5) with a radius of 3, the equation becomes ((x - 4)^2 + (y - 5)^2 = 3^2). Therefore, the equation of the circle is ((x - 4)^2 + (y - 5)^2 = 9).
It seems there is a small error in the equation you provided. A standard circle equation is typically in the form ((x - h)^2 + (y - k)^2 = r^2), where ( (h, k) ) is the center and ( r ) is the radius. If you meant ( x^2 + y^2 = 9 ), then the radius of the circle is ( r = \sqrt{9} = 3 ).
The answer is indeterminate. For example, if the equation is of the form x2 - 2ax + y2 - 2by = 25, all that can be said of the radius of the circle is that it is greater than 5.
The general form of the equation of a circle with center at the point ( (a, b) ) and a radius of length ( m ) is given by the equation ( (x - a)^2 + (y - b)^2 = m^2 ). Here, ( (x, y) ) represents any point on the circle. This equation expresses that the distance from any point on the circle to the center ( (a, b) ) is equal to the radius ( m ).