If you mean center (6, 4) and coordinate (2, 1) then it is: (x-6)^2 +(y-4)^2 = 25
If ... the square of (the x-coordinate of the point minus the x-coordinate of the center of the circle) added to the square of (the y-coordinate of the point minus the y-coordinate of the center of the circle) is equal to the square of the circle's radius, then the point is on the circle.
a diameter
Equation of circle: (x-3)^2 +(y-2)^2 = 8
In the coordinate plane, if the centre of the circle is at (a, b) then the equation is(x - a)^2 + (y - b)^2 = 2^2
The circles that have their centers on the y-axis are those that have the equation x^2 + (y-k)^2 = r^2, where k is the y-coordinate of the center of the circle and r is the radius of the circle. In this case, the x-coordinate of the center is 0 since it lies on the y-axis.
Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
(x - h)2 + (y - k)2 = r2 where h is the x coordinate of the center of the circle. where k is the y coordinate of the center of the circle. where x is the x coordinate of point (x,y) on the edge of the circle. where y is the y coordinate of point (x,y) on the edge of the circle. Additional assistance here: http://www.mathwarehouse.com/geometry/circle/equation-of-a-circle.php
A unit circle is a circle of radius 1. If it's center is at the origin of an xy-coordinate system, then the equation is x (squared) + y (squared) = 1
The x-coordinate of the circle's center changes when you move the circle horizontally. This is because the equation for a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle. Moving the circle horizontally shifts the circle left or right, changing the value of h.
If ... the square of (the x-coordinate of the point minus the x-coordinate of the center of the circle) added to the square of (the y-coordinate of the point minus the y-coordinate of the center of the circle) is equal to the square of the circle's radius, then the point is on the circle.
a diameter
Equation of a circle: (x-h)^2+(y-h)^2=r^2 k is the x-coordinate for the centre, h is the y-coordinate for the centre r=raduis if the equation is x^2+y^2=r^2, the centre of the circle is at (0,0)
Equation of circle: (x-3)^2 +(y-2)^2 = 8
-40
In the coordinate plane, if the centre of the circle is at (a, b) then the equation is(x - a)^2 + (y - b)^2 = 2^2
The circles that have their centers on the y-axis are those that have the equation x^2 + (y-k)^2 = r^2, where k is the y-coordinate of the center of the circle and r is the radius of the circle. In this case, the x-coordinate of the center is 0 since it lies on the y-axis.
The secant of a circle passes through the center of a circle sometimes