y = 1/3x+4
0909
- 1/3
It is -1/2
The second equation works out as y = -1/2x+6 therefore it is perpendicular
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
0909
negative 1
It is: 1/5
- 1/3
It is -1/2
The second equation works out as y = -1/2x+6 therefore it is perpendicular
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
It will be the positive reciprocal of -2 which is 1/2
the slope will be positive 1.5x the whole equation is y=4.5+1.5x
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
Equation of line: y = x+5 Equation of circle: x^2 +4x +y^2 -18y +59 = 0 The line intersects the circle at: (-1, 4) and (3, 8) Midpoint of line (1, 6) Slope of line: 1 Perpendicular slope: -1 Perpendicular bisector equation: y-6 = -1(x-1) => y = -x+7 Perpendicular bisector equation in its general form: x+y-7 = 0