The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
y = 0. You can get this from the slope-intercept equation of the line.
The straight line equation is: y = 2x
The equation of the line works out as: y = -3x+29
y = 3x
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
y = 0. You can get this from the slope-intercept equation of the line.
which equation has a slope of -1/2 and a graph that passes through (-3,4)?
sda
The straight line equation is: y = 2x
The equation of the line works out as: y = -3x+29
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
It is: y = -2x
y = -4x
y = 3x
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.