Points: (2, 2) and (6, 3)
Slope: 1/4
Equation: y = 1/4x+3/2
In standard form: x-4y+6 = 0
The standard form of the equation is 2x - y + 5 = 0
To find the equation of a line in standard form (Ax + By = C) that passes through the point (-5, 1) with a slope of 7, we can use the point-slope form first: (y - 1 = 7(x + 5)). Simplifying this gives (y - 1 = 7x + 35) or (y = 7x + 36). Rearranging to standard form results in (-7x + y = 36) or (7x - y = -36). Thus, the standard form of the equation is (7x - y = -36).
The straight line equation is: y = 2x
A standard form of a linear equation would be: ax + by = c
(3,1)(3,2)
The standard form of the equation is 2x - y + 5 = 0
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
To find the equation of a line in standard form (Ax + By = C) that passes through the point (-5, 1) with a slope of 7, we can use the point-slope form first: (y - 1 = 7(x + 5)). Simplifying this gives (y - 1 = 7x + 35) or (y = 7x + 36). Rearranging to standard form results in (-7x + y = 36) or (7x - y = -36). Thus, the standard form of the equation is (7x - y = -36).
It is (x + 2)^2 + (y + 3)^2 = 9
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
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The straight line equation is: y = 2x
Slope-intercept form
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y = x
A standard form of a linear equation would be: ax + by = c
(3,1)(3,2)