0
What else can I help you with?
What is the standard form of the equation of a circle with its center at (2 -3) and passing through the point (-2 0)?
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
How do you write an equation for a circle with a center?
Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
When does a secant of a circle pass through the center of the circle?
The secant of a circle passes through the center of a circle sometimes
If a circle is centered at the origin and the length of its radius is 6 What is the circle's equation?
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
Does a chord of a circle have to go through the center?
No, the cord of a circle does not have to go through the center of that circle. A chord that does go through the center of a circle is a special case and is called the diameter. A chord can connect any two points on a circle.
How do you write an equation in standard form of a circle with a center and radius?
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
What is the standard form of an equation where the poin 3-6 is on a circle whose orgin is the center?
9
What is a chord passing through the center of a circle?
a diameter
How do you Writing the Equation of a Circle in Standard Form?
(x - A)2 + (y - B)2 = R2 The center of the circle is the point (A, B) . The circle's radius is ' R '.
What is the standard form of the equation of a circle with its center at (2 -3) and passing through the point (-2 0)?
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
What is the equation of the circle with center at (3 2) and through the point (5 4).?
Equation of circle: (x-3)^2 +(y-2)^2 = 8
What equation represents the circle whose center is (-5,3) and that passes through the point (-1,3)?
-40
What is the center of the circle given by the equation (x - 3)2 (y - 9)2 16?
Well, honey, the center of that circle is simply the point (3, 9). You see, the equation you provided is in the form (x - h)² + (y - k)² = r², where (h, k) is the center of the circle. So, in this case, the center is at (3, 9). That's all there is to it, sugar.
How do you write an equation for a circle with a center?
Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
What is the standard form of an equation were the poin 3-6 is on a circle whose orgin is the center?
32+62=45 so the standard form is x2+y2=45
When does a secant of a circle pass through the center of the circle?
The secant of a circle passes through the center of a circle sometimes
Find an equation of the circle that has center 0 2 and passes through the origin.?
The equation of a circle with center (0,2) and radius r is x^2+(y-2)^2=r^2 Since it passes through (0,0) (the origin) 0^2+(0-2)^2=r^2 r^2=4 The equation of the circle is x^2+(y-2)^2=4
