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The equation, y = -4x - 3, is written in what's called slope-intercept form. The general equation for slope-intercept form is y = mx + b, where m is the slope of the line, and b is the y-intercept. So, for the equation in question, m = -4 and b = -3. Thus, the slope of the line is -4.
The equation of a line is y=mx+b, when m is the slope of the line and b is the y-intercept.
5
The equation of the line can be written as y = mx + b, where m is the slope and b is the y-intercept. Given that the slope is 3 and the y-intercept is (0, -10), the equation of the line is y = 3x - 10.
solve the equation for y to get the slope.y=-2x-1/2substitute (3,3) into the equation/3=2(3)+band solve for b.-3=+by=2x-3 is the equation with the same slope(parallel) and goes through (3,3)
The equation, y = -4x - 3, is written in what's called slope-intercept form. The general equation for slope-intercept form is y = mx + b, where m is the slope of the line, and b is the y-intercept. So, for the equation in question, m = -4 and b = -3. Thus, the slope of the line is -4.
The equation for the line is y = mx +b the slope is the value of m For example if y = 3x +4 the that is the equation that completely defines the line; its slope is 3
The equation of a line is y=mx+b, when m is the slope of the line and b is the y-intercept.
5
The equation of the line can be written as y = mx + b, where m is the slope and b is the y-intercept. Given that the slope is 3 and the y-intercept is (0, -10), the equation of the line is y = 3x - 10.
6
solve the equation for y to get the slope.y=-2x-1/2substitute (3,3) into the equation/3=2(3)+band solve for b.-3=+by=2x-3 is the equation with the same slope(parallel) and goes through (3,3)
The equation for a line is y = mx + b, where m is the slope and b is the y-intercept.
If you know the slope and x-intercept, writing the equation to a line is easy. For example, if you know the x-intercept to be 3, and the slope to be 2, then you plug it into the equation y=mx+b. At the point where the line hits the x-intercept, the y-value is 0, meaning you actually have a data point (3,0). Plug this into your equation: 0=3(2)+b 0=6+b -6=b b=-6 Then you put the equation together, as you know m and b: y=2x-6
y = mx + b y = 3x + 8.25
The equation of a line with slope m through a point (x0, y0) has equation: y - y0 = m(x - x0) Thus the equation of the line with slope 2 through the point (4, -3) has equation: y - (-3) = 2(x - 4) → y + 3 = 2x - 8 → y = 2x - 11
For a quadratic equation y=Ax2+Bx+C, the line of symmetry is given by x=-B/2ASo for the equation y=-x2+x+3, B is 1 and A is -1, so the line of symmetry isx=1/2