6
The equation of a line is y = mx + b where m is slope and b is y intercept (value at x = 0). if horizontal its slope is 0 and passes through y = -3 so y intercept is -3; equation is y = mx + b ; thus y = -3
A horizontal line has a slope of 0, so its y value does not change
→ the horizontal line through(3, -3) is y = -3.
It is y = -3.
-40
33
Point: (1, 4) Slope: -3 Equation: y = -3x+7
It passes through Quadrants II and IV. It also passes through the origin ... the point where the 'x' and 'y' axes cross. At that point, it's in all four quadrants.
Y=mx+b
The equation of a horizontal line is of the form y=k, where k is the y-coordinate of the point through which the line passes. Therefore, the equation of the horizontal line through the point (8, -10) is y = -10.
Assuming the point is (9, -4), the equation is y = -4.
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
The equation is [ y = 3 ].
sda
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
The equation is: y = 4x-22
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
414
The equation works out as: y = 5x+7
If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3
"14" is not a point; you need two coordinates to specify a point.