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How do you factor -x2 plus x plus 42?
-x2 + x + 42 = -[x2 - x - 42] = -[x2 - 7x + 6x - 42] = -[x*(x - 7) + 6*(x - 7)] = -(x - 7)*(x + 6)
How do you factor x2-x-42?
(x + 6) (x - 7)
What binomial is the factor of x2-13x 42?
(x - 6)(x - 7)
What is the factor x2 plus x minus 42?
(x + 7)(x - 6)
Factor x2 plus x - 42?
44
How do you factor -x2 plus x plus 42?
-x2 + x + 42 = -[x2 - x - 42] = -[x2 - 7x + 6x - 42] = -[x*(x - 7) + 6*(x - 7)] = -(x - 7)*(x + 6)
How do you factor x2-x-42?
(x + 6) (x - 7)
How do you factor x2 x 42?
If that's x^2 + x - 42, that factors to (x + 7)(x - 6)
What binomial is the factor of x2-13x 42?
(x - 6)(x - 7)
What is the factor x2 plus x minus 42?
(x + 7)(x - 6)
How do you factor x2 plus X-42?
It is: (x+7)(x-6) when factored
Factor x2 plus x - 42?
44
How would you factor x2-42?
44
Which of the binomials below is a factor of this trinomial x2 - 13x plus 42?
(x - 6)(x - 7)
What is a factor of x2 plus 19x - 42?
X2 + 19X - 42 = 0What two factors of - 42 add up to 19?(X - 2)(X + 21)----------------------FOIL and see the function reappear.X = 2X = - 21
What is the factor of X4 plus X2 - 42?
x4 + x2 - 42 Let x2 = t, so that x4 = t2 t2 + t - 42 since -42 = 7(-6) and 7 + (-6) = 1, then t2 + t - 42 = (t - 6)(t + 7) = (x2 - 6)(x2 + 7) By replacing t with x2. So we have, x4 + x2 - 42 = (x2 - 6)(x2 + 7) = [x2 - (square root of 6)2](x2 + 7) = (x - sq. root of 6 )(x + sq. root of 6)(x2 + 7)
What is the factorization of the trinomal below -x2 plus x plus 42?
-x2 + x + 42= -x2 + 7x - 6x + 42= 7x - x2 + 42 - 6x= x(7 - x) + 6(7 - x)= (7 - x)(x + 6)
