(2x + 1)(x + 3)
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You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)
2x2 + 7x + 3 = (2x + 1)(x + 3)If 2x2 + 7x + 3 = 0 then:(2x + 1)(x + 3) = 0⇒ (2x + 1) = 0 → x = -1/2or (x + 3) = 0 → x = - 3
(2x + 1)(x + 3) = 0; x = -0.5 or -3
(2x + 1) (x + 3) = 2x2 + 7x + 3
It is: 2x2-7x+6 = (2x-3)(x-2) when factored