(y + 7)(y + 7)
Doesn't factor evenly, use quadratic equation
(4x + 7)(16x2 - 28x + 49)
4849494949505050------394
a2(2a2-21a+49) a2(2a-7)(a-7)
n² - 10n + 24 = 0 You need two numbers that multiply to equal 24. They have to add to equal -10. -6 times -4 is 24 -6 plus -4 is -10 Your answer is (n - 6)(n - 4).
40n2 + 40n = 40n(n + 1) ------------------ That is as factored as far I can see it being factored.
(y + 7)(y + 7)
x2 - 14x + 49(x - 7) (x - 7)
(x + 7)(x2 - 7x + 49)
Doesn't factor evenly, use quadratic equation
To calculate the sum of 49 plus 49 plus 49 plus 49 plus 49, you would multiply 49 by 5, which equals 245. This is because addition is a form of repeated multiplication. So, 49 multiplied by 5 is 245.
Factoring requires you to reduce as much as possible. To factor 7x + 49, you remove the common factor of 7x and 49, which is 7, and multiply (7x + 49)/7 (which is x + 7) by 7, without actually simplifying. 7x + 49 = 7(x + 7) Then, if possible, do the same thing until it cannot be further factored.
(4x + 7)(16x2 - 28x + 49)
a + b + 4 is in its simplest form.
4849494949505050------394
Factor tree for 49:49/ \7 x 7497,7