If you mean: n2+16n+64 then it is (n+8)(n+8) when factored
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Conditional statement: If n2 equals 64, then n equals 8, where n2 equals 64 is the hypothesis, and n equals 8 is the conclusion. In order to obtain the converse of the conditional we reverse the 2 clauses, then the original conclusion becomes the new hypothesis and the original hypothesis becomes the new conclusion. So that, Converse: If n equals 8, then n2 equals 64.
No, 4 is a factor of 64.
16n
Yes because its discriminant is greater than zero.
Had it not been for 64, the nth term would be given by t(n) = 3*n2 However, this cannot be the case because then t(4) would have been 48, not 64.