Answer: (x-2)
(x2-5x+6)/(x-3)
=(X-3)X(X-2)/(X-3) <-You factor the expression (x2-5x+6) and get (x-3)(x-2)
=(X-2) <-The (x-3)'s in the numerator and denominator cancel each other out (because an expression divided by the same expression equals one) and thus you are left with (x-2).
(5x - 2)(x - 5)
(2x-3)(x-1)
2(5x - 1)(3x - 2)
After long division, (2x2-5x+5)/(x-2) = 2x-1+3/(x-2).
That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (5 plus or minus the square root of -15) divided by 2.x = 2.5 + 1.9364916731037085ix = 2.5 - 1.9364916731037085iwhere i is the square root of negative one.
(x - 1)(5x + 7)
(5x - 2)(x - 5)
x = 0,1
There are no rational factors.
which of the following is a factor of x2 - 5x - 6
(x-1)(x-4)
(2x-3)(x-1)
(2x - 1)(5x + 8)
That would depend on the plus or minus value of 2 which has not been given.
2(5x - 1)(3x - 2)
After long division, (2x2-5x+5)/(x-2) = 2x-1+3/(x-2).
10x - 5x + 5x = 10x