(b - x)(ab - xy)
Arthur Pythagoras he say AB2 = AC2 + BC2, so AB2 = 81 + 144 ie AB = sqrt 225 = 15 cm
The question is poorly specified, since the given triangle can be right angled at A or C. If it is right angled at A, then bc2 = ab2 + ac2 so that ab2 = 100 - 16 = 84 and ab = sqrt(84) = 9.165 Or it is right angled at C, and ab2 = bc2 + ca2 = 100 + 16 = 116 so that ab = sqrt(116) = 10.770
The LCM is 42a2b2.
b*ab = ab2 Suppose b*ab = ab + b2. Assume a and b are non-zero integers. Then ab2 = ab + b2 b = 1 + b/a would have to be true for all b. Counter-example: b = 2; a = 3 b(ab) = 2(3)(2) = 12 = ab2 = (4)(3) ab + b2 = (2)(3) + (2) = 10 but 10 does not = 12. Contradiction. So it cannot be the case that b = 1 + b/a is true for all b and, therefore, b*ab does not = ab + b2
Linear
The molecular geometry associated with AB2 molecules according to VSEPR theory is linear. This means that the two bonding pairs are arranged in a straight line with a bond angle of 180 degrees.
Can't tell u in general if a or b, depends on what AB2 is, e.g. CO2 is linear, H2O is tent shaped (corner at midst atom: 105o) but not trigonal as you'd call it.Anyhow c, d, E are unusual for tri-atomic.H2O is not in the form AB2. When in the form AB2 the ideal bond angle is 180 degrees or linear.See the link below.
√(ab2) = (√a)*b
AB2
The GCF is ab2
In the graphical method using the Gibbs adsorption isotherm equation, the surface excess concentration of AB2 can be obtained by plotting the surface excess Gibbs free energy against the bulk concentration of AB2 at equilibrium. The intercept of the linear plot on the y-axis gives the surface excess concentration of AB2 at the surface. This method helps quantify the extent of the surface concentration of AB2 in the system.
Let consider the right triangle ABC with hypotenuse AB and heigth AC then base is BC Pythagorean theorem states that AB2=AC2+BC2 so BC2=AB2-AC2 then BC=sqrt(AB2-AC2)
ab2
(a -b) · (a2+ab+b2) = (a3+a2b+ab2) - (a2b+ab2+b3) = a3 -b3 (a+b) · (a2 -ab+b2) = (a3 -a2b+ab2) +(a2b -ab2+b3) = a3+b3 More generally: (a ∓ b) · (an-1 ±an-2b +an-3b2 ±an-4b3 +±...+a(±b)n-2 +(±b)n-1) = an ± bn. The mixed terms cancel out themselves.
4
ab(a - b)