x2+4x-32 = (x-4)(x+8) when factored
x2 + 4x + 6 can not be factored. If you want, you can reduce it to an expression with a single x term by comleting the square: x2 + 4x + 6 = x2 + 4x + 4 + 2 = (x + 2)2 + 2
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
x2 + 4x - 96 = (x - 8)(x + 12).
4x+8
x2+4x-32 = (x-4)(x+8) when factored
x2 - 4x - 32 = (x - 8)(x + 4)
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
(x - 4) or (x + 8)
x2 + 4x + 3 = (x + 1)(x + 3)
x2 + 4x + 6 can not be factored. If you want, you can reduce it to an expression with a single x term by comleting the square: x2 + 4x + 6 = x2 + 4x + 4 + 2 = (x + 2)2 + 2
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
x2 - 12x + 32 = 0 x2 - 8x - 4x +32 = 0 x(x -8) - 4(x -8) = 0 (x - 4)(x - 8) = 0 x = 4 or x = 8
x2 + 4x - 96 = (x - 8)(x + 12).
X2 + 4xx(x + 4)=======
You can work this out with long division, by checking to see if (x2 - 1) is a factor of (2x4 + 4x3 - x2 + 4x - 3). It is. Unfortunately, the WikiAnswers system is somewhat limited in depicting things such as long division, so we won't be able to represent it here. In short though, (2x4 + 4x3 - x2 + 4x - 3) / (x2 + 1) is equal to 2x2 + 4x - 3. which means that: (x2 + 1) / (2x4 + 4x3 - x2 + 4x - 3) = (x2 + 1) / (x2 + 1)(2x2 + 4x - 3) = 1 / (2x2 + 4x - 3)
x(x + 4)(x - 4) or x3 - 16x