x3 + 13x2 + 42x = x(x + 6)(x + 7).
x3 - 7x2 + 6x =x (x2 - 7x + 6) =x (x - 6) (x - 1)
x3 + 2x2 - 35x = x(x + 7)(x - 5)
x3 - 7x2 + 6x = x(x2 - 7x + 6) = x(x2 - x - 6x + 6) = x[x(x - 1) - 6(x - 1)] = x2(x - 1) - 6x(x - 1) = (x2 - 6x)(x - 1)
If: x3+1 = 65 Then: x3 = 65-1 And: x3 = 64 So: x = 4 by means of the cube root function on the calculator
x3 + 13x2 + 42x = x(x + 6)(x + 7).
x3 - 7x2 + 6x =x (x2 - 7x + 6) =x (x - 6) (x - 1)
x3 + 2x2 - 35x = x(x + 7)(x - 5)
It is: (x2 + 5x) (x + 8)
x(x + 8)(x + 5)
x(x + 9)(x + 5)
The inverse of a number is 1 divided by that number. So the inverse of x3 + 1 is 1/(x3 + 1).
x3 - 12x2 + 35x = x (x2 - 12x + 35) = x (x - 7) (x - 5)
x3 - 7x2 + 6x = x(x2 - 7x + 6) = x(x2 - x - 6x + 6) = x[x(x - 1) - 6(x - 1)] = x2(x - 1) - 6x(x - 1) = (x2 - 6x)(x - 1)
(xn+2-1)/(x2-1)
x(x - 1)(x - 13)
4