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What is the final velocity and height of a ball thrown from a bridge with an upward velocity of 5 meter per seconds and hits the ground after 5 and .5 seconds?
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A marble dropped from a bridge strikes the water in 5 seconds. What is the speed with which it strikes and the height of the bridge?
Velocity final = vi + at = 49 m/s displacement = vi * t + ½2at² = 122.5 m vi = 0 a ≈ 9.8 t = 5
The height h of a ball thrown into the air with an initial vertical velocity of 48 feet per second from a height of 5 feet above the ground is given by the equation?
At any time 't' seconds after the ball is released,until it hits the ground,h = 5 + 48 t - 16.1 t2
If a cricket jumps off the ground with an initial vertical velocity of 4 ft per second what is an equation the height in ft of the crisket as a function of time in seconds since it jumped?
4ft*Ns=H
What would be the change in velocity for a 10 gram object dropped from the roof of a 20 meter building if it takes 2 seconds to reach the ground Hint acceleration due to gravity is 9.8 ms²?
Acceleration = (change in velocity) / (time for the change)9.8 = (change in velocity) / (2 seconds)9.8 x 2 = change in velocity = 19.6 meters per second .Hint: The mass of the object and the height of the building are there just tothrow you off balance. You don't need either of them to answer the question.
Will a ball drop rest reach the ground quicker than the one lunched from the same height but with and initial horizontal velocity?
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
A rock is dropped from a height of 60 m and is in free fall. What is the velocity of the rock as it reaches the ground 3.5 seconds later?
The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.
A marble dropped from a bridge strikes the water in 5 seconds. What is the speed with which it strikes and the height of the bridge?
Velocity final = vi + at = 49 m/s displacement = vi * t + ½2at² = 122.5 m vi = 0 a ≈ 9.8 t = 5
What is the velocity of a ball that has a 3.03 second hit to the ground?
To calculate the velocity of the ball, we need to know the height from which it was dropped. If the ball was dropped from rest, we can use the formula for free fall motion: velocity = (acceleration due to gravity * time). Assuming the acceleration due to gravity is 9.81 m/s^2, the velocity of the ball hitting the ground after 3.03 seconds would be around 29.7 m/s.
The height h of a ball thrown into the air with an initial vertical velocity of 48 feet per second from a height of 5 feet above the ground is given by the equation?
At any time 't' seconds after the ball is released,until it hits the ground,h = 5 + 48 t - 16.1 t2
A rock falls off a bridge and hits the water 8 seconds later How high is the bridge?
The height of the bridge can be calculated using the formula: distance = 0.5 * acceleration due to gravity * time^2. Given that the rock takes 8 seconds to hit the water, the height of the bridge would be approximately 313.6 meters.
If a cricket jumps off the ground with an initial vertical velocity of 4 ft per second what is an equation the height in ft of the crisket as a function of time in seconds since it jumped?
4ft*Ns=H
A suspension bridge is supported from a height of 30 feet. The length of the wire used to suspend the bridge from the ground to the top is 65 feet. What is the angle of elevation from the base of the?
A suspension bridge is supported from a height of 30 feet. The length of the wire used to suspend the bridge, from the ground to the top, is 65 feet. What is the angle of elevation from the base of the bridge to the point of suspension?
What is the rock's approximate velocity just prior to hitting the ground?
To answer this question one would need to know the rock's initial height and velocity.
A stone is dropped from a bridge and it takes 2.1 seconds to hit the ground How high is the bridge?
Assuming the stone was dropped from rest, we can calculate the height of the bridge using the kinematic equation: h = 0.5 * g * t^2, where h is the height of the bridge, g is the acceleration due to gravity (9.8 m/s^2), and t is the time of fall (2.1 seconds). Plugging in the values, we get h = 0.5 * 9.8 * (2.1)^2 = 22.33 meters. Therefore, the height of the bridge is approximately 22.33 meters.
What do you you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
What happens when you release a ball from a height at rest?
It will fall with increasing velocity due to gravity and reach the peak velocity just before hitting the ground.
What would be the change in velocity for a 10 gram object dropped from the roof of a 20 meter building if it takes 2 seconds to reach the ground Hint acceleration due to gravity is 9.8 ms²?
Acceleration = (change in velocity) / (time for the change)9.8 = (change in velocity) / (2 seconds)9.8 x 2 = change in velocity = 19.6 meters per second .Hint: The mass of the object and the height of the building are there just tothrow you off balance. You don't need either of them to answer the question.
