sqrt(4n2) = 2n
4n2
when n = 0 it equals -25 when n = 1 it equals -36 when n = 2 it equals -39 etc
Yes. Any odd integer, k, is of the form 2n+1 where n is an integer. then k2 = (2n + 1)2 = 4n2 + 4n + 1. The first two terms are even so the three-term total must be odd.
5 x 16 + 4 x 9 = 80 + 36 = 116
8n + 4n2 -8n
sqrt(4n2) = 2n
9m2+ 9mn- 4n2
2mn + 4n2 and 5m2 - 7mn
4n2 + 5m2 - 5mn
4n2 is one expression. You need at least two to find a GCF
If you mean: 4n^2+62n-32 then it is (2n-1)(n+16) when factored after dividing all terms by 2
4n2
4n2-25 = 0 4n2=25 n2=6.25 n=sqrt(6.25) n= +2.5 or -2.5
when n = 0 it equals -25 when n = 1 it equals -36 when n = 2 it equals -39 etc
It t is an odd multiple of 5, you can express it as 5(2n+1), where "n" is some integer. The square of that expression is 25(2n+1)2 = 25(4n2+4n+1) = 100n2+100n+25. Since the first two terms are multiples of 100 (remember, "n" is an integer), you have some multiple of 100, plus 25 - in other words, a number that ends with 25.
Yes. Any odd integer, k, is of the form 2n+1 where n is an integer. then k2 = (2n + 1)2 = 4n2 + 4n + 1. The first two terms are even so the three-term total must be odd.