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y=14 here is how you go about solving the problem 3y-2y=14 first set up equation y=14 combine like terms and get 1y but we do not need 1 in front because the variable has invisible 1
When solving an algebraic equation such as this one, just remember to do what you need to in order to get the variable (y) by itself. And always do the same thing to both sides of the equation. So we start with: -1/2 + 3y = 4y Next combine the y's by subtracting 3y from both sides, which gives us: -1/2 + 3y - 3y = 4y - 3y -1/2 = y so the answer is y= -1/2
rewrite first equation: x = 15 - y substitute into second equation for x: 4(15 - y) + 3y = 38 distribute and simplify: 60 - y = 38 solve: y = 22 plug back into first equation: x = -7 -OR- multiply first equation by -3: -3x - 3y = -45 add new equation to second equation: 1x + 0y = -7 or x = -7 plug back into first equation: y = 22
4y + 7 - y = 10 + 3y My next step is to combine the y's on the left, 3y + 7 = 10 + 3y If I then subtract 3y from both sides I obtain 7 = 10 which is not a true statement. Hence, the equation that you presented is invalid.
The equation for 3y + 3y = -1 is 3y + 3y = -1.
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x - 2y = 04x - 3y = 15From the first equation, x = 2y.SUBSTITUTING this value of x in the second equation,4*(2y) - 3y = 15 ie 8y - 3y = 15 or 5y = 15 so that y = 3and then, x = 2y gives x = 2*3 = 6Answer: x = 6, y = 3
2x+3y=40-2x+2y=20Since 2x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2x from both sides.3y=-2xDivide each term in the equation by 3.(3y)/(3)=-(2x)/(3)Simplify the left-hand side of the equation by canceling the common terms.y=-(2x)/(3)if you were solving for x It would be x=-(3y)/2
y=14 here is how you go about solving the problem 3y-2y=14 first set up equation y=14 combine like terms and get 1y but we do not need 1 in front because the variable has invisible 1
x = 3y x - 3y = 3y - 3y x - 3y = 3y - 3y x - 3y = 0
When solving an algebraic equation such as this one, just remember to do what you need to in order to get the variable (y) by itself. And always do the same thing to both sides of the equation. So we start with: -1/2 + 3y = 4y Next combine the y's by subtracting 3y from both sides, which gives us: -1/2 + 3y - 3y = 4y - 3y -1/2 = y so the answer is y= -1/2
rewrite first equation: x = 15 - y substitute into second equation for x: 4(15 - y) + 3y = 38 distribute and simplify: 60 - y = 38 solve: y = 22 plug back into first equation: x = -7 -OR- multiply first equation by -3: -3x - 3y = -45 add new equation to second equation: 1x + 0y = -7 or x = -7 plug back into first equation: y = 22
4y + 7 - y = 10 + 3y My next step is to combine the y's on the left, 3y + 7 = 10 + 3y If I then subtract 3y from both sides I obtain 7 = 10 which is not a true statement. Hence, the equation that you presented is invalid.
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
2x plus 3y is not an equation, it is an expression.
Removing the brackets: 4y-4-y-2 = 3y-6 simplified