The problem is: -x + 3y = -2
Are you trying to solve for x? Or for y?
If you're solving for x, subtract 3y from both sides of your equation, and then divide both sides by negative one. The steps will look like this:
-x = -2 - 3y -------------------> x = 2 + 3y
If you're solving for y, add x to both sides of the equation, and divide both sides by 3. Here are your results:
3y = -2 + x -------------------> y = (x - 2) / 3
x+3y=2 x= -5 y = 1
2x-3y=13
are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}
x + y = 6 so that -x = y - 6 -x + 3y = -2 that is, y - 6 + 3y = -2 or 4y = 4 or y = 1 and then -x = y - 6 = -5 so that x = 5
x = 5, y = -1
x+3y=2 x= -5 y = 1
2x-3y=13
are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}
5x+3y
The answer is - not are : (5, 1).
x + y = 6 so that -x = y - 6 -x + 3y = -2 that is, y - 6 + 3y = -2 or 4y = 4 or y = 1 and then -x = y - 6 = -5 so that x = 5
(3, 2) because x = 3 and y = 2
x = 5, y = -1
x=-2, y=2
x=2 y=7 5x+3y= 5 7 x 2 x 3 ____ _____ 10 21 21 + 10 _______ 31
x=1y=2x+3y=2*1 + 3y=5
2x+3y=13 3x-y=3 x=2