1
x+3y=2 x= -5 y = 1
2x-3y=13
are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}
x + y = 6 so that -x = y - 6 -x + 3y = -2 that is, y - 6 + 3y = -2 or 4y = 4 or y = 1 and then -x = y - 6 = -5 so that x = 5
x = 5, y = -1
x+3y=2 x= -5 y = 1
2x-3y=13
5x+3y
are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}
The answer is - not are : (5, 1).
x + y = 6 so that -x = y - 6 -x + 3y = -2 that is, y - 6 + 3y = -2 or 4y = 4 or y = 1 and then -x = y - 6 = -5 so that x = 5
(3, 2) because x = 3 and y = 2
x = 5, y = -1
x=-2, y=2
x=2 y=7 5x+3y= 5 7 x 2 x 3 ____ _____ 10 21 21 + 10 _______ 31
x=1y=2x+3y=2*1 + 3y=5
2x+3y=13 3x-y=3 x=2