Let's call the smaller number n and the larger (n+9). Making the second statement into an equation:
5n = 3(n+9) + 7
5n = 3n + 27 + 7
5n = 3n + 34
2n = 34
n = 17 and n+9 = 26
Check: Do the number fit the problem?
5 * 17 = 7 + 3 * 26
85 = 7 + 78 TRUE, the numbers 17 and 26 are a valid solution for the problem.
You subtract the smaller from the larger.
x > 16
Ignore the signs and subtract the smaller number from the larger one.
They are 6, 8, 10 and 12.
Yes, rational numbers are larger than integer because integers are part of rational numbers.
Subtract the smaller from the larger.
You subtract the smaller from the larger.
x > 16
If the order of the pairs of numbers doesn't matter (that is the pairs (1, 11) and (11, 1) are considered the same) then there are 89 such pairs.If the order does matter (that is the pairs (1, 11) and (11, 1) are considered different) then there are 178 such pairs.There must be one number larger than the other.The smaller number must be at least 1, so the larger number must be at least 11.The larger number must be at most 99, so the smaller number must be at most 89.Thus, looking at the smaller numbers, it can be one of the numbers 1 to 89 - a total of 89 possibilities - each of which has a corresponding larger number.Therefore there are 89 combinations of 2 integers from the number 1-99 that have a difference of 10.If however, the order of the integers is important, then the smaller number can be the first number or second number, which means that there are twice as many possible pairs, giving 178 permutations of 2 integers from the numbers 1-99 that have a difference of 10.
44 & 45
4,6,8,10
Ignore the signs and subtract the smaller number from the larger one.
They are 6, 8, 10 and 12.
Yes, rational numbers are larger than integer because integers are part of rational numbers.
Subtract smaller from larger, divide answer by larger. (L-S)/L
subtract the smaller number from the larger number.
Negative Numbers.