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It is the equality sign that makes it an equation because without the equality sign it would be an algebraic expression.

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Q: What is the focus of an equation?
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What is the standard equation for vertex at origin opens down 1 and 76 units between the vertex and focus?

Since the vertex is at the origin and the parabola opens downward, the equation of the parabola is x2 = 4py, where p < 0, and the axis of symmetry is the y-axis. So the focus is at y-axis at (0, p) and the directrix equation is y = -p. Now, what do you mean with 1 and 76 units? 1.76 units? If the distance of the vertex and the focus is 1.76 units, then p = -1.76, thus 4p = -7.04, then the equation of the parabola is x2 = -7.04y.


What does 4 stands for in equation of parabola square of square of y equals 4ax?

A parabola with an equation, y2 = 4ax has its vertex at the origin and opens to the right. It's not just the '4' that is important, it's '4a' that matters. This type of parabola has a directrix at x = -a, and a focus at (a, 0). By writing the equation as it is, the position of the directrix and focus are readily identifiable. For example, y2 = 2.4x doesn't say a great deal. Re-writing the equation of the parabola as y2 = 4*(0.6)x tells us immediately that the directrix is at x = -0.6 and the focus is at (0.6, 0)


What is the equation for an ellipse with center at the origin ,one focus at (1,1) and the length of semi major axise is 4.?

This equation is equal to the first one because it produces the same results, always. ... TL;DR - The circle equation is what you get when you multiply all terms from the ellipse equation by the radius. x^2/a^2 + y^2/b^2 = 1 is an ellipse equation. Well, a circle has a radius where a and b are the same.


How do you solve parabola equation having lb focus at 0 3?

There is not enough information. You need either the directrix or vertex (or some other item of information).


What could be the equation of a parabola with its vertex at 1 3?

4