10
I'm assuming that you mean x^2 = 8y?
Anyway, by comparing the equation with the standard equation for a parabola (y^2 = 4ax) and swapping round x and y, you can see that a = 2. Thus, the directrix is y + 2 = 0 and the focus is (0, 2).
There is no equation (nor inequality) in the question so there can be no graph - with or without an axis of symmetry.
Answer this question… What is the line of symmetry of the graph of the equation ? A. x = -2 B. x = -4 C. x = -16 D. x = -8
Did you mean a parabola with equation y=3x^2? The line of symmetry is x=0 or the y-axis.
A parabola has a single focus point. There is a line running perpendicular to the axis of symmetry of the parabola called the directrix. A line running from the focus to a point on the parabola is going to have the same distance as from the point on the parabola to the closest point of the directrix. In theory you could look at a parabola as being an ellipse with one focus at infinity, but that really doesn't help any. ■
When x = -5
The axis of symmetry is x = -2.
The form is not specified in the question so it is hard to tell. But two parabolas with different vertices can certainly have the same axis of symmetry.
"From the geometric point of view, the given point is the focus of the parabola and the given line is its directrix. It can be shown that the line of symmetry of the parabola is the line perpendicular to the directrix through the focus. The vertex of the parabola is the point of the parabola that is closest to both the focus and directrix."-http://www.personal.kent.edu/~rmuhamma/Algorithms/MyAlgorithms/parabola.htm"A line perpendicular to the axis of symmetry used in the definition of a parabola. A parabola is defined as follows: For a given point, called the focus, and a given line not through the focus, called the directrix, a parabola is the locus, or set of points, such that the distance to the focus equals the distance to the directrix."-http://www.mathwords.com/d/directrix_parabola.htm
If a quadratic function has the points (-4,0) and (14,0), what is equation of the axis of symmetry?
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
There is no equation (nor inequality) in the question so there can be no graph - with or without an axis of symmetry.
Since the vertex is at the origin and the parabola opens downward, the equation of the parabola is x2 = 4py, where p < 0, and the axis of symmetry is the y-axis. So the focus is at y-axis at (0, p) and the directrix equation is y = -p. Now, what do you mean with 1 and 76 units? 1.76 units? If the distance of the vertex and the focus is 1.76 units, then p = -1.76, thus 4p = -7.04, then the equation of the parabola is x2 = -7.04y.
X=-b/2a
Answer this question… What is the line of symmetry of the graph of the equation ? A. x = -2 B. x = -4 C. x = -16 D. x = -8
7-8=d-s
-1
Did you mean a parabola with equation y=3x^2? The line of symmetry is x=0 or the y-axis.