Cos(x) = 1 - x2/2! + x4/4! - x6/6! + ... where x is measured in radians
cos = adjacent / hypotenuse
Sin= Opposite/Hypotenuse Cos= Adjacent/Hypotenuse Tan= Opposite/Adjacent
It depends on which leg is 850... If the leg on the bottom is 850, then you do 850/cos(20) (which gives you 904.55), if it is the leg on the side, then you do 850/sin(20) (which gives you 2485.233). You get this by solving for the formula Cos(Angle)=Adjacent/Hypotenuse, or Sin(Angle) = Opposite/Hypotenuse.
Cos(58) = 4/Hypotenuse so H = 4/Cos(58) = 7.55 units.
the adjacent side over the hypotenuse
Two methods ;- #1 ; Use Pythagoras, if the lengths of the other two sides are known. h^(2) = s(1)&(2) + s(2)^(2) In words, 'The hypotenuse squared is the sum of the squares of the other two sides. #2 ; Use Trigonometry (trig.) is the length of one side and an angle are known . Hence Sin(angle) = opposite / hypotenuse hypotenuse = opposite / Sin(angle) or Cos(angle) = adjacent/hypotenuse hypotenuse = adjacent/Cos(angle).
Cos(angle) = adjacent / hypotenuse. Cos(a) = a/h Substitute Cos(X) = 5/13 = 0.384615... A = Cos^*-1( 0.384615 .... A = 67.38013505... degrees.
cos = adjacent / hypotenuse
Sin= Opposite/Hypotenuse Cos= Adjacent/Hypotenuse Tan= Opposite/Adjacent
Depending on the information given;- If two other(shorter) sides are known, use Pythagoras. h^(2) = a^(2) + b^(2) If one angle and one side are given then you use Trigonometry . Sin(angle) = opposite/ hypotenuse hypotenuse = opposite/Sin(angle) or Cos(angle) = adjacent/hypotenuse hypotenuse = adjacent/ Cos(Angle).
Adjacent side / Hypotenuse
It depends on which leg is 850... If the leg on the bottom is 850, then you do 850/cos(20) (which gives you 904.55), if it is the leg on the side, then you do 850/sin(20) (which gives you 2485.233). You get this by solving for the formula Cos(Angle)=Adjacent/Hypotenuse, or Sin(Angle) = Opposite/Hypotenuse.
Cos(58) = 4/Hypotenuse so H = 4/Cos(58) = 7.55 units.
No. It has to lie in between -1 an +1 inclusive. Cos x = adjecent/hypotenuse and for cos x to be greater than 1, you need the adjacent to be bigger than the hypotenuse. The hypotenuse is always the biggest side.
Cos is the ratio between adjacent side (of the given angle thieta) to the hypotenuse of the triangle.
the adjacent side over the hypotenuse
A ladder leaning against a 20ft wall, with an angle of 32 degrees with respect to the wall, must be 24ft long. cos(theta) = adjacent over hypotenuse cos(32) = 20 / hypotenuse hypotenuse = 20 / cos(32) hypotenuse = 23.58