Cos(x) = 1 - x2/2! + x4/4! - x6/6! + ... where x is measured in radians
cos = adjacent / hypotenuse
Sin= Opposite/Hypotenuse Cos= Adjacent/Hypotenuse Tan= Opposite/Adjacent
It depends on which leg is 850... If the leg on the bottom is 850, then you do 850/cos(20) (which gives you 904.55), if it is the leg on the side, then you do 850/sin(20) (which gives you 2485.233). You get this by solving for the formula Cos(Angle)=Adjacent/Hypotenuse, or Sin(Angle) = Opposite/Hypotenuse.
Cos(58) = 4/Hypotenuse so H = 4/Cos(58) = 7.55 units.
the adjacent side over the hypotenuse
Cos(angle) = adjacent / hypotenuse. Cos(a) = a/h Substitute Cos(X) = 5/13 = 0.384615... A = Cos^*-1( 0.384615 .... A = 67.38013505... degrees.
cos = adjacent / hypotenuse
Sin= Opposite/Hypotenuse Cos= Adjacent/Hypotenuse Tan= Opposite/Adjacent
Adjacent side / Hypotenuse
It depends on which leg is 850... If the leg on the bottom is 850, then you do 850/cos(20) (which gives you 904.55), if it is the leg on the side, then you do 850/sin(20) (which gives you 2485.233). You get this by solving for the formula Cos(Angle)=Adjacent/Hypotenuse, or Sin(Angle) = Opposite/Hypotenuse.
Cos(58) = 4/Hypotenuse so H = 4/Cos(58) = 7.55 units.
Cos is the ratio between adjacent side (of the given angle thieta) to the hypotenuse of the triangle.
the adjacent side over the hypotenuse
No. It has to lie in between -1 an +1 inclusive. Cos x = adjecent/hypotenuse and for cos x to be greater than 1, you need the adjacent to be bigger than the hypotenuse. The hypotenuse is always the biggest side.
A ladder leaning against a 20ft wall, with an angle of 32 degrees with respect to the wall, must be 24ft long. cos(theta) = adjacent over hypotenuse cos(32) = 20 / hypotenuse hypotenuse = 20 / cos(32) hypotenuse = 23.58
It is: cos^-1(12/13) = 22.61986495 degrees
Opposite over hypotenuse. Sin=opposite/hypotenuse cos=adjacent/hypotenuse tan=opposite/adjacent