Cos(x) = 1 - x2/2! + x4/4! - x6/6! + ... where x is measured in radians
cos = adjacent / hypotenuse
Sin= Opposite/Hypotenuse Cos= Adjacent/Hypotenuse Tan= Opposite/Adjacent
It depends on which leg is 850... If the leg on the bottom is 850, then you do 850/cos(20) (which gives you 904.55), if it is the leg on the side, then you do 850/sin(20) (which gives you 2485.233). You get this by solving for the formula Cos(Angle)=Adjacent/Hypotenuse, or Sin(Angle) = Opposite/Hypotenuse.
Cos(58) = 4/Hypotenuse so H = 4/Cos(58) = 7.55 units.
the adjacent side over the hypotenuse
Cos(angle) = adjacent / hypotenuse. Cos(a) = a/h Substitute Cos(X) = 5/13 = 0.384615... A = Cos^*-1( 0.384615 .... A = 67.38013505... degrees.
cos = adjacent / hypotenuse
Sin= Opposite/Hypotenuse Cos= Adjacent/Hypotenuse Tan= Opposite/Adjacent
Adjacent side / Hypotenuse
It depends on which leg is 850... If the leg on the bottom is 850, then you do 850/cos(20) (which gives you 904.55), if it is the leg on the side, then you do 850/sin(20) (which gives you 2485.233). You get this by solving for the formula Cos(Angle)=Adjacent/Hypotenuse, or Sin(Angle) = Opposite/Hypotenuse.
Cos(58) = 4/Hypotenuse so H = 4/Cos(58) = 7.55 units.
Cos is the ratio between adjacent side (of the given angle thieta) to the hypotenuse of the triangle.
No. It has to lie in between -1 an +1 inclusive. Cos x = adjecent/hypotenuse and for cos x to be greater than 1, you need the adjacent to be bigger than the hypotenuse. The hypotenuse is always the biggest side.
the adjacent side over the hypotenuse
A ladder leaning against a 20ft wall, with an angle of 32 degrees with respect to the wall, must be 24ft long. cos(theta) = adjacent over hypotenuse cos(32) = 20 / hypotenuse hypotenuse = 20 / cos(32) hypotenuse = 23.58
It is: cos^-1(12/13) = 22.61986495 degrees
Opposite over hypotenuse. Sin=opposite/hypotenuse cos=adjacent/hypotenuse tan=opposite/adjacent